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lianna [129]
4 years ago
6

A 4.50-volt personal stereo uses 1950 joules of electrical energy in one hour. what is the electrical resistance of the personal

stereo?
Physics
1 answer:
saveliy_v [14]4 years ago
6 0
The stereo uses an energy of E=1950 J in a time t=1 h=3600 s, therefore the power of the stereo is given by
P= \frac{E}{t}= \frac{1950 J}{3600 s}=0.54 W

We also know that the power of an electrical device is related to its voltage, V, and its resistance, R, by the following equation
P= \frac{V^2}{R}
therefore, we can rearrange the equation to calculate the resistance of the stereo:
R= \frac{V^2}{P}= \frac{(4.5 V)^2}{0.54 W}=37.5 \Omega
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