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Zanzabum
3 years ago
10

This equation is known as the ideal gas law, and it can be used to predict the behavior of many gases at relatively low pressure

. From this equation, you can see that as the temperature of a gas increases,
A) the pressure of the gas increases.
B) the number of moles of gas will go down.
C) either the pressure of the gas, the volume of the gas, or both, will increase.
D) either the pressure of the gas, the volume of the gas, or both, will decrease.
Physics
1 answer:
Masja [62]3 years ago
6 0
The correct answer is 
<span>C) either the pressure of the gas, the volume of the gas, or both, will increase.

In fact, the ideal gas law can be written as
</span>pV=nRT
<span>where 
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas

We can see that if the temperature T increases, then the term on the right in the equation increases, therefore the term on the left should increase as well. In order for this to be possible, at least one between p and V should increase, or also both of them. Therefore, the correct answer is C.</span>
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A transverse wave on a string is described by the wave function
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The period of the transverse wave from what we have here is 0.5

<h3>How to find the period of the transverse wave</h3>

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1 year ago
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a 6 iron. The acceleration due to gravity on t
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vₓ = v* cos (25º) = 23 m/s * 0.906 = 20.8 m/s

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y = voy*t - (\frac{1}{2}*\frac{g}{6} * t^{2} )

If the total displacement in the vertical direction is 0 (which means  that the time if the total time of flight), we can solve for t, as follows:

t = \frac{voy*12}{g} = \frac{9.72 m/s*12}{9.8m/s2} = 11. 9 s

On earth, this time could be calculated in the same way:

t = \frac{voy*12}{g} = \frac{9.72 m/s*2}{9.8m/s2} = 1.98 s

As the time is defined by the vertical movement, we can find the horizontal distance travelled on the moon, as follows:

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Δx = v₀ₓ * t = 20.8 m/s * 1.98 s = 41.3 m

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b) As we have just found, the time of flight on the moon and on the earth are as follows:

tmoon = 11. 9 s

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