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a_sh-v [17]
3 years ago
8

A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following fun

ction:
f(t) = -16t^2 + 44t + 12

Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground?

Physics
2 answers:
snow_lady [41]3 years ago
8 0

The correct answer would be  1.375 < t < 3  i hope this helps anyone


Vikki [24]3 years ago
3 0

Answer:

Domain is 1.375 s to 3 s

Explanation:

It is given that, A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function:

f(t)=-16t^2+44t+12

We have to find the domain of the graph of the function when the basketball falls from its maximum height to the ground. It is shown in the attached graph.

It is clear that, the domain of the graph is from 1.375 s to 3 s. Its maximum height is 42.25 feet.

Hence, this is the required solution.      

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Three parallel wires of length l each carry current Iin the same direction. They’re positioned at the vertices of an equilateral
cluponka [151]

Answer:

F = μi²l/πa

Explanation:

The magnetic force F on a length of wire, l carrying a current i in a magnetic field B is given by

F = Bilsinθ      

The magnetic field due to one wire of length, l carrying a current, i at a distance a from it is given by B = μi/2πa

So, the force on the first wire due to the second wire is F₁ = Bilsinθ = μiilsinθ/2πa = μi²lsinθ/2πa

the force on the first wire due to the third wire is F₂ = Bilsinθ = μiilsinθ/2πa = μi²lsinθ/2πa

Since the magnetic field due to the one wire is perpendicular to the length of the other wire its field acts upon, θ = 90

So, F₁ = μi²lsinθ/2πa = μi²lsin90/2πa = μi²l/2πa and

F₂ = μi²lsinθ/2πa = μi²lsin90/2πa = μi²l/2πa

Since the angle between F₁ and F₂ is 60° (since it is an equilateral triangle)

The resultant force F is thus

F = √(F₁² + F₂² + 2F₁F₂cos60°)

F = √(F₁² + F₂² + 2F₁F₂ × 0.5)

F = √(F₁² + F₂² + 2F₁F₂)   (since F₁ = F₂)

F = √(2F₁² + 2F₁²) = √(4F₁²)

F = 2F₁

F = 2μi²l/2πa

F = μi²l/πa

6 0
3 years ago
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Work is done on an object when an applied force causes the object to move in the same direction as the force.
Lelu [443]

Answer:yes

Explanation:

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3 0
4 years ago
A flute player hears four beats per second when she compares her note to an 880 Hz tuning fork (note A). She can match the frequ
ludmilkaskok [199]

Answer:

884Hz

Explanation:

Beats is the absolute difference between two frequencies therefore

Beats = f1-f2

4=f1-880

F1=880+4

F1=884Hz

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3 years ago
The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit
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Answer:

fr = ½ m v₀²/x

Explanation:

This exercise the body must be on a ramp so that a component of the weight is counteracted by the friction force.

The best way to solve this exercise is to use the energy work theorem

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          ΔK = 0 - ½ m v₀²

We substitute

         - fr x = - ½ m v₀²      

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