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nekit [7.7K]
3 years ago
10

For the following situations, describe the contact and non-contact forces that are involved.

Physics
2 answers:
Sonja [21]3 years ago
8 0
I think is b not a 100% sure but maybe.
musickatia [10]3 years ago
7 0

Answer:

a. the book is exerting force down on the shelf (due to gravity) while the shelf is exerting force back up at the book.

b. when the soccer player kicks the ball, this is applied force. As the ball soars through the air and lands on the ground, the friction ends the movement of the ball.

c. the compass detects the Earth's natural magnetic feild. This force is non contact, since there is no physical touch between magnetic feilds and the compass.

d. when the child is just sitting on the hill on the sled, this is a contact force. The child is pushing down on the sled and the sled pushes back at the child. When he or she slides off down the hill, this contact force is put to a stop due to friction.

Explanation:

Explanation above for each situation.

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A current-carrying wire is bent into a circular loop of radius R and lies in an xy plane. A uniform external magnetic field B in
Ilya [14]

Answer:

 F = 2π I R B

Explanation:

The magnetic force is described by the equation.

      F = q v x B = i L  x B

Where i is the current, L is a vector that points in the direction of the current (length) and B is the magnetic field.

This equation can be used in scalar form and the direction of the force found by the right hand ruler, the thumb goes in the direction of L, the fingers extended in the direction of B and the palm of the hand indicates the direction of the force if the load is positive

     F = i L B sin θ

In this case the wire is in the xy plane and the z-axis field whereby they are perpendicular, θ = 90º and sin 90 = 1

     F = i L B

The loop length is

    L = 2π R

    F = i 2π R B

    F = 2π I R B

The force is in the loop

8 0
2 years ago
An object accelerates from rest to 85m/s over a distance of 36m. What acceleration did it experience?
Marizza181 [45]
Suvat
we have s, u, v and we want a
the suvat equation with these values in is: v^2 = u^2 - 2as
so a = (-v^2 + u^2)/-2s 
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a = (-85^2 + 0^2)/-2*36 = 7225/72 = 100.3... ms^-2
6 0
3 years ago
A race car travels 40 m/s around a banked (45° with the horizontal) circular (radius = 0.20 km) track. What is the magnitude of
OLEGan [10]

Answer:

c)F_{net} = 0.640 kN

Explanation:

As we know that resultant force is the net force that is acting on the system

As per Newton's II law we know that net force is product of mass and acceleration

so we will have

F_{net} = ma

here we know

m = 80 kg

for circular motion acceleration is given as

a_c = \frac{v^2}{R}

a_c = \frac{40^2}{200} = 8 m/s^2

now we have

F_{net} = 80 \times 8

F_{net} = 640 N

F_{net} = 0.640 kN

7 0
3 years ago
Which combination of elements will form an ionic bond?
Anna007 [38]

Answer:

C

Explanation:

8 0
2 years ago
The specialty of an athlete on the women's track team is the pole vault. She has a mass of 48 kg and her approach speed is 8.9 m
Lyrx [107]

Answer:

H = 3.9 m

Explanation:

mass (m) = 48 kg

initial velocity (initial speed) (U) = 8.9 m/s

final velocity (V) = 1.6 m/s

acceleration due to gravity (g) = 9.8 m/s^{2}

find the height she raised her self to as she crosses the bar (H)

from energy conservation, the change in kinetic energy = change in potential energy

0.5m(V^{2} - [test]U^{2}[/tex]) = mg(H-h)

where h = initial height = 0 since she was on the ground

the equation becomes

0.5m(V^{2} - [test]U^{2}[/tex]) = mgH

0.5 x 48 x (1.6^{2} - [test]8.9^{2}[/tex]) = 48 x 9.8 x H

-1839.6 = 470.4 H  (the negative sign indicates a decrease in kinetic energy so we would not be making use of it further)

H = 3.9 m

4 0
3 years ago
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