All categories

3 years ago

For the following situations, describe the contact and non-contact forces that are involved.

Physics

2 answers:

Sonja [21]3 years ago

8 0

I think is b not a 100% sure but maybe.

musickatia [10]3 years ago

7 0

Answer:

a. the book is exerting force down on the shelf (due to gravity) while the shelf is exerting force back up at the book.

b. when the soccer player kicks the ball, this is applied force. As the ball soars through the air and lands on the ground, the friction ends the movement of the ball.

c. the compass detects the Earth's natural magnetic feild. This force is non contact, since there is no physical touch between magnetic feilds and the compass.

d. when the child is just sitting on the hill on the sled, this is a contact force. The child is pushing down on the sled and the sled pushes back at the child. When he or she slides off down the hill, this contact force is put to a stop due to friction.

Explanation:

Explanation above for each situation.

You might be interested in

The internal energy of a material is determined by

vazorg [7]

<span>The combined amount of kinetic and potential energy of its molecules

</span>

8 0

3 years ago

Read 2 more answers

Help pls ... will give brainlist

Ghella [55]

I, i’m pretty sure sorry if it’s wrong

6 0

2 years ago

A flywheel with radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.400 rad/s2.For a po

oksian1 [2.3K]

Answer:

$0.12\ m/s^2$

Explanation:

Given that,

The radius of a flywheel, r = 0.3 m

Angular acceleration of a flywheel, $\alpha =0.4\ rad/s^2$

We need to find the magnitude of the tangential acceleration after 2.00 s of acceleration.

The relation between the tangential and angular acceleration is given by :

$a_t=r\alpha \\\\a_t=0.3\times 0.4\\\\a_t=0.12\ m/s^2$

So, the required magnitude of tangential acceleration is $0.12\ m/s^2$ .

6 0

3 years ago

A frictionless toy car is placed on a ramp, which is inclined at an unknown angle with respect to the horizontal. Starting from

NikAS [45]

The final speed of the toy car at the end of the given time period is 3.58 m/s.

The given parameters;

distance traveled by the car, s = 1.2 m
time of motion of the car, t = 0.67 s
initial velocity of the car, u = 0

The acceleration of the car is calculated as;

$s = ut + \frac{1}{2} at^2\\\\1.2 = 0 + 0.5\times a\times (0.67)^2\\\\1.2 = 0.225a\\\\a = \frac{1.2}{0.225} \\\\a = 5.33 \ m/s^2$

The final velocity of the toy car is calculated as;

$v_f^2 = u^2 + 2as\\\\v_f^2 = 0 + 2\times 5.33 \times 1.2\\\\v_f^2 = 12.792\\\\v_f = \sqrt{12.792} \\\\v_f = 3.58 \ m/s$

Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.

Learn more here: brainly.com/question/20352766

6 0

2 years ago

(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is 3.85 108 m. Find

Goshia [24]

Answer:

It took 1.28 seconds to his voice to reach the Earth via radio waves.

Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensities, that radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies, the highest being that of gamma rays, followed by X-rays, ultraviolet rays and the visible region , and those of lower frequencies, which correspond to infrared, microwave and radio waves.

Light propagates as electromagnetic wave in vacuum with a speed of $3x10^{8}m/s$ . Therefore, radio waves will have in vacuum the same speed.