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3 years ago

Why do we need the periodic table? First to answer get brainless!!!!!

2 answers:

3 0

The periodic table is the most important chemistry reference there is. It arranges all the known elements in an informative array. Elements are arranged left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass.

EleoNora [17]3 years ago

3 0

It was used to predict the chemical and elemental properties.

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If an otherwise empty pressure cooker is filled with air of room temperature and then placed on a hot stove, what would be the m

Xelga [282]

Answer:

The magnitude of the net force F₁₂₀ on the lid when the air inside the cooker has been heated to 120 °C is $\frac{135.9}{A}N$

Explanation:

Here we have

Initial temperature of air T₁ = 20 °C = ‪293.15 K

Final temperature of air T₁ = 120 °C = 393.15 K

Initial pressure P₁ = 1 atm = ‪101325 Pa

Final pressure P₂ = Required

Area = A

Therefore we have for the pressure cooker, the volume is constant that is does not change

By Chales law

P₁/T₁ = P₂/T₂

P₂ = T₂×P₁/T₁ = 393.15 K× (‪101325 Pa/‪293.15 K) = ‭135,889.22 Pa

∴ P₂ = 135.88922 KPa = 135.9 kPa

Where Force = $\frac{Pressure}{Area}$ we have

Force = $F_{120}=\frac{135.9}{A}N$ .

4 0

4 years ago

How coal power plants produce electrical energy to power our homes

balandron [24]

Coal plants use a boiler to produce steam.

3 0

3 years ago

Which vector has a y-component with a length of 3? A. C B. d C. a D. b

goldenfox [79]

Answer:

Option C : a

Explanation:

4 0

3 years ago

Which statement about the composition of ocean and water is true?

Allushta [10]

I think B would be the best answer

7 0

3 years ago

How to calculate? I got 15000N for (a)

MAXImum [283]

Your answer for part a is correct. Using Newton's 3rd Law, the force on the rocket by the exhaust leaving the rocket is the same magnitude (opposite direction) as the downward force applied to the exhaust.
In part b the net force is the upward force from the exhaust thrust minus the downward force of gravity:

$F_{net}=F_{thrust}-mg=15,000N-1500kg \times 1.6 \frac{m}{s^2}=12,600N$

Then using the Second Law, we get for part c:

$F=ma \\ a= \frac{F}{m} = \frac{12600N}{1500kg} =8.4 \frac{m}{s^2}$

The force and acceleration are in the upward direction

3 0

3 years ago