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jolli1 [7]
3 years ago
10

Which property of a substance is not affected by physical changes?

Physics
1 answer:
LiRa [457]3 years ago
6 0
Reactivity is not affected by physical changes.

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BigorU [14]

Measuring the heat of chemical reactions or physical changes.

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What are the answers for numbers 2 & 3?
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The answer is 6 i no this because im in high school this app is for high schoolers now I'll answer more. of ur questions if u make them have more points now u shouldn't play this game because ur prob in elementary but any ways the answer is 6
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Write three nuclear equations to represent the nuclear decay sequence that begins with the alpha decay of u-235 followed by a be
vazorg [7]

Answer:

We know that in the decay process the sum of molecular number as well as molecular weight should be constant.

The following three reaction are as follows

1 .

Alpha decay  of parent nuclide

_{92}^{235}\textrm{U} \rightarrow _{90}^{231}\textrm{Th}+_{2}^{4}\textrm{alpha }

The molecular number of alpha particle is 2 and molecular weight is 4 g/mol.

2.

Beta decay of daughter nuclide

_{90}^{231}\textrm{Th}\rightarrow _{91}^{231}\textrm{Pa}+_{-1}^{0}\textrm{beta}+v

v is the neutrino emission,The charge on the beta particle is zero.

3.

Alpha decay

_{91}^{231}\textrm{Pa}\rightarrow_{89}^{227}\textrm{Pa}+_{2}^{4}\textrm{alpha}

5 0
4 years ago
Read 2 more answers
What type of objects cannot pull to magmets
boyakko [2]

Answer:

brass, copper, zinc and aluminum, wood, glass, and plastic

Explanation:

7 0
3 years ago
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While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83
allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

\beta_{dB} = 10log_{10}\frac{I}{I_0}

Where,

\beta_{dB}= Sound intensity level in decibels

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB

So:

10log_{10}(\frac{32I}{I_0}) = 83

10log(\frac{I}{I_0})+10log(32) = 83

10log(\frac{I}{I_0})= 83-10log(32)

10log(\frac{I}{I_0})= 67.948dB

Therefore the sound intensity due to one person is 67.948dB

8 0
3 years ago
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