Answer:
It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.
V^2=U^2+2*a*x
V=0 (as it is at max height)
U=30ms^-1 (initial speed)
a=-g /-9.8ms^-2 (as it is moving against gravity)
x is the variable you want to calculate (height)
0=30^2+2*(-9.8)*x
x=-30^2/2*-9.8
x=45.92m
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>:</em><em>)</em>
Answer:
ok so
Explanation:
Im not sure rn but ill get back to you.
Answer:
The work done by this engine is 800 cal
Explanation:
Given:
100 g of water
120°C final temperature
22°C initial temperature
30°C is the temperature of condensed steam
Cw = specific heat of water = 1 cal/g °C
Cg = specific heat of steam = 0.48 cal/g °C
Lw = latent heat of vaporization = 540 cal/g
Question: How much work can be done using this engine, W = ?
First, you need to calculate the heat that it is necessary to change water to steam:

Here, mw is the mass of water

Now, you need to calculate the heat released by the steam:

The work done by this engine is the difference between both heats:

Answer:
7.468 kN
Explanation:
Here the force of 7468 Newton is given.
Some of the prefixes of the SI units are
kilo = 10³
Mega = 10⁶
Giga = 10⁹
The number is 7468.0
Here, the only solution where the number of significant figures is kilo
1 kilonewton = 1000 Newton


So 7468 N = 7.468 kN