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Leviafan [203]
3 years ago
6

The student quickly discovers that placing the marshmallow over the flame is more effective than heating the marshmallow on the

side of the flame. According to the information above, what type of heat transfer is present when the marshmallow is above the fire that is not present when the marshmallow is on the side of the fire
Physics
1 answer:
ANEK [815]3 years ago
4 0

Answer:

The answer is convection.

Explanation:

There are three types of heat transfer: conduction, convection and radiation.

  • Conduction occurs when two objects touch each other and transfer heat.
  • Convection occurs when an object heats its surrounding fluid (like air, or water) and, since the hot fluids are less dense than the cold ones, they go up. So convection is a type of heat transfer that usually goes from down to up.
  • Radiation occurs when objects emanate heat in the form of electromagnetic waves that propagates in all directions.

So in this case, when the marshmallow is above the fire, it is exposed to convection, which does not occur when it is on the side of the fire.

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Part B
Katena32 [7]

Answer:

While slavery was the major issue separating the North and South, it was not slavery itself that sparked the conflict. The South wanted to secede from the Union, and the North refused. While President Abraham Lincoln personally opposed slavery, he recognized that it was legal under the U.S. Constitution at the time. He also recognized that few in the North were ready to go to war to free the slaves. For Lincoln and the northern majority, preservation of the Union was the foremost goal.

4 0
3 years ago
Can someone help me?!!!!!
ladessa [460]

Answer:

magnitude: 21.6; direction: 33.7 degrees

Explanation:

When we multiply a vector by a scalar, we have to multiply each component of the vector by the scalar number. In this case, we have

vector: (-3,-2)

Scalar: -6

so the vector multiplied by the scalar will have components

(-3\cdot (-6), -2 \cdot (-6))=(18,12)

The magnitude is given by Pythagorean's theorem:

m=\sqrt{18^2+12^2}=21.6

and the direction is given by the arctan of the ratio between the y-component and the x-component:

\theta = tan^{-1} (\frac{12}{18})=33.7^{\circ}

3 0
3 years ago
How would i solve these problems, nobody in my class understands and there is a substitute
drek231 [11]

find acceleration force divided by Mass

a=f/m

6 0
3 years ago
In general, an organism will be more likely to develop phobias of __________.
BARSIC [14]

Answer:

a) dangers faced during natural circumstances

7 0
2 years ago
The linear charge density on the inner conductor is and the linear charge density on the outer conductor is
Lubov Fominskaja [6]

Complete Question

The complete question is  shown on the first uploaded image (reference for Photobucket )

Answer:

The  electric field is  E = -1.3 *10^{-4} \ N/C

Explanation:

 From the question we are told that

    The linear charge density on the inner conductor is  \lambda _i  =  -26.8 nC/m  =  -26.8 *10^{-9} C/m

    The linear charge density on the outer conductor is

  \lambda_o  = -60.0 nC/m  =  -60.0 *10^{-9} \ C/m

     The position of interest is r =  37.3 mm =0.0373 m

Now this position we are considering is within the outer conductor so the electric field  at this point is due to the inner conductor (This is because the charges on the conductor a taken to be on the surface of the conductor according to Gauss Law )

Generally according to Gauss Law

         E (2 \pi r l) =  \frac{ \lambda_i }{\epsilon_o}

=>    E =  \frac{\lambda _i }{2 \pi *  \epsilon_o * r}

substituting values  

       E =  \frac{ -26 *10^{-9} }{2 * 3.142 *  8.85 *10^{-12} * 0.0373}

       E = -1.3 *10^{-4} \ N/C

The  negative  sign tell us that the direction of the electric field is radially inwards

    =>   |E| = 1.3 *10^{-4} \ N/C

5 0
3 years ago
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