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Lostsunrise [7]
3 years ago
5

How many atoms of phosphorus are in 8.90 mole of copper (ii) phosphate?

Chemistry
2 answers:
elena-s [515]3 years ago
4 0
<span>for every 1 mole of Cu3(PO4)2, there are 2 moles of phosphorus. We also know that 1 mole of Cu3(PO4)2 has 6.022 x 10^23 atoms (Avogadro's number
</span>8.90 moles Cu3(PO4)22 moles P1 mol Cu3(PO4)21 mol Cu3(PO4)2<span>6.022 x 10^23 atoms
</span><span> (53.5958 x 10^23)/2 = 26.7979 x 10^23 atoms of P</span>
castortr0y [4]3 years ago
4 0

Answers er:

Explanation:

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Answer:

Newton’s law of inertia is illustrated in tests with crash dummies, seat belts, and airbags, wherein the object stays in motion unless there is an unbalanced force applied to it.

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2 years ago
Explain why biodiversity in an ecosystem is important.
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It reduces the chance of an extinction given a natural disaster. If there is more diversity and lets say a wildfire happens, more species would survive the event to repopulate the area
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3 years ago
What is the limiting reactant when 5.6 moles of aluminum react with 6.2 moles of water?
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The limiting  reactant  when 5.6  moles   of aluminium react  with  6.2  moles   of water   is

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      <u><em>Explanation</em></u>

The  balanced    equation is as below

2 Al +3 H2O  →  Al2O3  +3 H2

The mole ratio  of Al :Al2O3  is 2:1  therefore  the  moles  of  Al2O3

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The   mole  ratio  of H2O: Al2O3  is 3:1 therefore  the  moles  of Al2O3  produced

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7 0
3 years ago
Read 2 more answers
An analytical chemist is titrating 242.5mL of a 1.200M solution of hydrazoic acid HN3 with a 0.3400M solution of NaOH . The pKa
fgiga [73]

<u>Answer:</u> The pH of the solution is 12.61

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}       ......(1)

  • <u>For hydrazoic acid:</u>

Molarity of hydrazoic acid solution = 1.200 M

Volume of solution = 242.5 mL

Putting values in equation 1, we get:

1.200M=\frac{\text{Moles of hydrazoic acid}\times 1000}{242.5mL}\\\\\text{Moles of hydrazoic acid}=0.291mol

  • <u>For NaOH:</u>

Molarity of NaOH solution = 0.3400 M

Volume of solution = 1006 mL

Putting values in equation 1, we get:

0.3400M=\frac{\text{Moles of NaOH}\times 1000}{1006mL}\\\\\text{Moles of NaOH}=0.342mol

The chemical reaction for hydrazoic acid and NaOH follows the equation:

                   HN_3+NaOH\rightarrow NaN_3+H_2O

<u>Initial:</u>           0.291        0.342

<u>Final:</u>                  0          0.051                 0.291      0.291

Volume of solution = 242.5 + 1006 = 1248.5 mL = 1.2485 L    (Conversion factor:  1 L = 1000 mL)

  • <u>For NaOH left:</u>

Left moles of NaOH = 0.051 moles

Volume of the solution = 1.2485 L

Putting values in equation 1, we get:

\text{Molarity of NaOH}=\frac{0.051mol}{1.2485L}=0.0408M

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=0.0408M

Putting values in above equation, we get:

pOH=-\log(0.0408)\\\\pOH=1.39

To calculate pH of the solution, we use the equation:

pH+pOH=14\\\\pH=14-1.39=12.61

Hence, the pH of the solution is 12.61

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