3 years ago

NEED HELP!!! :( Math!!!

1 answer:

8 0

The "divisor" in synthetic division is most conveniently the value of the zero of the binomial term. Here, that is x=5. You also need to make sure you include all of the coefficients in the "dividend", putting zero where terms are missing.

The appropriate choice is A.

You might be interested in

Assume the monthly interest rate is 1/12 of the annual interest rate . you maintain an average balance of $450 on your credit ca

masya89 [10]

Answer:

The monthly interest payment would be $ 9

Step-by-step explanation:

Given,

The average balance of the credit card = $ 450,

Annual rate of interest = 24%,

∵ Monthly interest rate is 1/12 of the annual interest rate,

Thus, the monthly interest rate = $\frac{1}{12}\text{ of }24\%$

$=2\%$

Hence, the monthly interest payment = 2% of credit card balance

= 2% of 450

$=\frac{2\times 450}{100}$

$=\frac{90}{10}$

= $ 9

3 0

3 years ago

A family of 12 went to the local Italian restaurant for dinner. Every family member

mojhsa [17]

12c + 3a + 6d = total bill when d stands for dessert and a stands for appitizer and 12 stands for drinks and meals

4 0

3 years ago

Read 2 more answers

✨a Pls help I will park you as brainlist promise ✨✨

svlad2 [7]

A. I am pretty sure that is right

4 0

2 years ago

Read 2 more answers

The coordinates of a point on a coordinate grid are (?1, 5). The point is reflected across the x-axis to obtain a new point. The

4vir4ik [10]

D. (?1, ?5) because it is only reflected across the x-axis, so it only effects the Y coordinates.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=15%20x%5E%7B2%7D%20%2B14x-49%3D0" id="TexFormula1" title="15 x^{2} +14x-49=0" alt="15 x^{2} +1

Alex777 [14]

$15x^2+14x-49=0\\\\
Terms:\\
a=15\ \ \ \ b=14\ \ \ \ c=-49\\
Quadratic\ Formula:\\\\
x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\
x=\dfrac{-14\pm\sqrt{196+2,940}}{30}\\\\
x=\dfrac{-14\pm\sqrt{3,136}}{30}\\\\
x=\dfrac{-14\pm56}{30}$

$Roots:\\\\
x'=\dfrac{-14+56}{30}\\\\
x'=\dfrac{42}{30}\\\\
x'=\dfrac{21}{15}\\\\
\boxed{x'=\dfrac{7}{5}}\\\\\\\\
x''=\dfrac{-14-56}{30}\\\\
x''=\dfrac{-70}{30}\\\\
\boxed{x''=\dfrac{-7}{3}}$

8 0

3 years ago

Read 2 more answers