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lys-0071 [83]
4 years ago
8

The chemistry teacher asked George to transfer an ideal gas from container A to container B. Container B is half the size of con

tainer A. If the temperature and moles of gas stay constant during transfer, the rate of collisions will _______________ and the pressure will __________
Chemistry
2 answers:
Rzqust [24]4 years ago
7 0
I think the answer is increase; increase

Allisa [31]4 years ago
6 0

Explanation:

According to the ideal gas equation, PV = nRT.

where,               P = pressure,                  V = volume

                         n = number of moles,     R = gas constant

                         T = temperature

Since, pressure is inversely proportional to volume. As container B is half in size as compared to container A. Therefore, pressure will increase when gas is added to container B.

Also, there will be more number of collisions between the molecules. Due to this there will be increase in rate of collisions.

Thus, we can conclude that for the given situation if the temperature and moles of gas stay constant during transfer, the rate of collisions will increase and the pressure will also increase.

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The number of valence electrons = group number
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Riley is doing an experiment working with friction. He wants to find two ways to modify an object that could increase or decreas
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Consider the following reaction: AB(s)⇌A(g)+B(g) . At equilibrium, a 10.9 L container at 650 K contains A(g) at a pressure of 0.
irina1246 [14]

Answer:

pA = 0.095 atm

pB = 0.303 atm

Explanation:

Step 1: the reaction

AB(s) ⇔ A(g) + B(g)

Kp = pA * pB

⇒ with Kp = equilibrium constant

Kp = 0.126 * 0.23  ⇒ Kp = 0.02898

Since the container will be compressed to half of its original volume, means that he pressure will be doubled.

⇒pA = 0.252

⇒pB =0.46

To establish this equilibrium, each pressure has to be lowered by x

⇒pA = 0.252 - x

⇒pB = 0.46 - x

Kp = 0.02898 = (0.252 - x)(0.46-x)

0.02898 = 0.11592 - 0.252x -0.46x + x²

-x² + 0.712x - 0.08694 = 0

D= b² - 4ac

⇒ D = 0.712² -4*(-1) *(-0.08694) = 0.506944‬ -0.34776‬ =0.159184

x = (-b ± √D)/2a  

x = (-0.712 ± √0.159184)/(2*-1)  = (-0.712 ± 0.398978696)/-2

x = 0.156510652 or x= 0.555489348

x = 0.555489348 is impossble or the pressure would be negative

x=0.156510652

pA =0.252 - 0.156510652 = 0.095489348 atm

pB = 0.46 - 0.156510652 = 0.303489348 atm

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valentina_108 [34]

Answer : The electrons in a bond between two iodine atoms are shared equally and non-polar.

Explanation :

Non-polar covalent bond : It is a type of bond that is present between the two similar and different atoms. This type of bond is formed when the electrons are shared equally between the atoms.

This type of bond is termed as non-polar because of the electronegativity difference between the atoms is negligible.

The given molecule I_2 is formed by the equal sharing of electrons and the bond formed between the iodine-iodine is non-polar due to negligible electronegativity difference.

Therefore, the electrons in a bond between two iodine atoms are shared equally and non-polar.

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