All categories

3 years ago

I need to make up an experiment !! Please help

Chemistry

1 answer:

katen-ka-za [31]3 years ago

7 0

Question: Baking a Cake Without Flour.

Hypothesis: I think that when I remove the flour from the standard cake recipe, I'll end up with a flat but tasty cake.

Procedure: I baked two cakes during my experiment. For my control, I baked a cake following a normal recipe. I used the Double Fudge Cake recipe on page 292 of the Betty Crocker Cookbook. For my experimental cake, I followed the same recipe but left out the flour. I first obtained a 2-quart mixing bowl.

Results: My control cake, which I cooked for 25 minutes, measured 4 cm high. Eight out of ten tasters that I picked at random from the class found it to be an acceptable dessert. After 25 minutes of baking, my experimental cake was 1.5 cm high and all ten tasters refused to eat it because it was burnt to a crisp.

What did I learn?/Conclusion: Since the experimental cake burned, my results did not support my hypothesis. I think that the cake burned because it had less mass, but cooked for the same amount of time. I propose that the baking time be shortened in subsequent trials.

I hope this helped :))

You might be interested in

Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t

Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

$Q_1=m\times \Delta H_{fusion}$

where,

$Q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

$\Delta H_{fusion}$ = enthalpy change for fusion = $3.35\times 10^5J/Kg$

Now put all the given values in $Q_1$ , we get:

$Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J$

<u>For process 2 :</u>

$Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})$

where,

$Q_2$ = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

$c_{p,l}$ = specific heat of liquid water = $4186J/Kg^oC$

$T_1$ = initial temperature = $0^oC$

$T_2$ = final temperature = $100^oC$

Now put all the given values in $Q_2$ , we get:

$Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC$

$Q_2=4.186\times 10^5J$

From this we conclude that, $Q_1$ that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0

3 years ago

What formula results when Ca+2 and Br -1 ions bond?

olga nikolaevna [1]

CaBr2
Because of the criss cross method of switching the charges

3 0

3 years ago

What is the pH of a 3.5 x 10-5 M solution of HCl?

Luden [163]

Answer:

pH = 4.45

Explanation:

We need to find the pH of $3.5\times 10^{-5}\ M$ solution of HCl. We know that, pH of a solution is given by :

$pH=-log[H]^+$

Put all the values,

$pH=-log[3.5\times 10^{-5}]\\\\pH=4.45$

So, the pH of the solution of HCl is 4.45.

5 0

3 years ago

Convert 100 °F to °C

Dima020 [189]

Answer:

37.8 Degrees Celcius is your answer.

6 0

3 years ago

Read 2 more answers

Which of the following increases as the concentration of a colored solution increases? wavelenght transmittance absorbance b) A

iris [78.8K]

Answer:

a) Absorbance

b) The absorb light most strongly in 580nm

Explanation:

Beer-Lambert law relates concentration with light absorbance. The more concentrated solution are the more molecules and the most absorbance.

Wavelenght depends of composition of solution and doesn't change with different concentrations of the same solution.

Transmittance is inversely proportional to absorbance. Thus, the more concentrated solution the less transmittance.

Colored compounds are absorb energy of visible radiation. The colour that we see is a result of the absortion of complimentary colour (Colour wheel). Thus, a blue-green solution absorb energy of ≈600 nm. Thus, the absorb light most strongly in 580nm.

I hope it helps!

6 0

4 years ago