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ikadub [295]
3 years ago
12

The function f(x) = 7 – 4x + x2 written in vertex form is f(x) = (x – 2)2 + 3. What is the axis of symmetry for the function?

Mathematics
2 answers:
Harrizon [31]3 years ago
5 0
Hello,

f(x)=x²-4x+7=x²-4x+4+3=(x-2)²+3

Axe of symmetry is x=2 passing throught the vertex.

ryzh [129]3 years ago
3 0

Answer:

Step-by-step explanation:

The vertex form of the equation is f(x) = (x-2)² + 3

Since in the vertex form of the parabola standard form of the equation should be f (x) = ( x-h )² + k

Where ( h, k) is the vertex

By comparing the standard equation of parabola with the given function.

vertex will be (2, +3)

and line of symmetry will be x = 2 passing through vertex.

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All rectangles are quadrilaterals because a quadrilateral has 4 sides and all rectangles have 4 sides so that one is correct
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A farmer owns a field with an area of 0.037 km2. The farmer buys another field with an area of 9600 m2. What is the total area o
Vlad1618 [11]

Answer:

0.0946km²

Step-by-step explanation

Area of the farmland owned = 0.037km²

Area of farm land bought = 9600m²

Convert m² to km²

1m² = 1e-6 km²

9600m² = 0.000001 * 9600

9600m² = 0.0576km²

Total area on km² = 0.037km²+0.0576km²

Total area on km²  = 0.0946km²

5 0
3 years ago
What are the solutions of the equation (x – 3)2 + 2(x – 3) -8 = 0? Use u substitution to solve.
Andrej [43]

Answer:

x = -1 and x = 5

Step-by-step explanation:

<em>What are the solutions of the equation (x – 3)² + 2(x – 3) -8 = 0? Use u substitution to solve.</em>

<em />

(x – 3)² + 2(x – 3) -8 = 0   -------------------------------------------------------(1)

To solve this problem, we will follow the steps below;

let u = x-3

we will replace x-3 by u in the given equation:

(x – 3)² + 2(x – 3) -8 = 0  

u² + 2u -8 = 0  ----------------------------------------------------------- --------------(2)

We will now solve the above quadratic equation

find two numbers such that its product gives -8 and its sum gives 2

The two numbers are 4 and -2

That is; 4×-2 = -8    and 4+(-2) = 2

we will replace 2u by (4u -2u)  in equation (2)

u² + 2u -8 = 0

u² + 4u - 2u -8 = 0

u(u+4) -2(u+4) = 0

(u+4)(u-2) = 0

Either  u + 4 = 0

            u = -4

or

u-2 = 0

u = 2

Either u = -4    or u = 2

But  u = x-3

x = u +3

when u = -4

x = u + 3

x = -4 + 3

x=-1

when u = 2

x = u + 3

x = 2 + 3

x=5

Therefore, x = -1  and  x =5

x

6 0
3 years ago
I need help please with this
yaroslaw [1]
The answer is 24
Explanation: no need for one :)
7 0
3 years ago
50 points + brainliest
xxTIMURxx [149]
Solving this problem involves repeated application of the distance formula. In order to figure out which vertices we need to connect to another vertex, we should first plot the points on the coordinate plane to get an idea of what the polygon looks like. To form the sides of this polygon (which is, in our case, a pentagon), we'll need to connect the points in the following pairs:

(-2, -2) and (3, -3)
(3, -3) and (4, -6)
(4, -6) and (1, -6)
(1, -6) and (-2, -4)
(-2, -4) and (-2, -2)

In case you forgot, the distance formula is simply an application of the Pythagorean Theorem that treats the x-distance and y-distance between two points as the "legs" of a right triangle, and the shortest distance between them as the "hypotenuse."

If a and b are the legs of a right triangle, and c is the hypotenuse, the Pythagorean Theorem can be written as:

a^2+b^2=c^2

Or, if we're just looking for the value of c:

c=\sqrt{a^2+b^2}

Since the hypotenuse in our case represents <em>distance</em>, it's more descriptive to rename that variable <em>d</em>. Also, the "legs" a and b in this problem represent the distances between the x and y components of the two points. If we take any two points (x_1,y_1) and (x_2,y_2), the distance between the x components of those points would be their difference, x_2-x_1, and the distance between the y components would be y_2-y_1. Substituting that all in, the distance formula becomes:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

All that's left to do now is substitute our specific points into the formula for each side of the polygon:

(-2, -2) and (3, -3):
d=\sqrt{(3-(-2))^2+(-3-(-2))^2}\\ d=\sqrt{(3+2)^2+(-3+2)^2}\\ d=\sqrt{5^2+(-1)^2}\\ d=\sqrt{25+1}\\ d=\sqrt{26}\\ d\approx5.1

(3, -3) and (4, -6)
d=\sqrt{(4-3)^2+(-6-(-3))^2}\\ d=\sqrt{1^2+(-6+3)^2}\\ d=\sqrt{1+(-3)^2}\\d=\sqrt{1+9}\\ d=\sqrt{10}\\ d\approx3.2

(4, -6) and (1, -6)
d= \sqrt{(1-4)^2+(-6-(-6))^2} \\ d= \sqrt{(-3)^2+0^2} \\ d= \sqrt{9} \\ d=3

(1, -6) and (2, -4)
d= \sqrt{(2-1)^2+(-4-(-6))^2}\\ d= \sqrt{1^2+(-4+6)^2}\\ d= \sqrt{1+2^2}\\ d= \sqrt{1+4} \\ d= \sqrt{5}\\ d\approx2.2

(2, -4) and (-2, -2)
d= \sqrt{(-2-2)^2+(-2-(-4))^2}\\ d= \sqrt{(-4)^2+(-2+4)^2} \\ d= \sqrt{16+2^2}\\ d= \sqrt{16+4}\\ d= \sqrt{20} \\ d\approx4.5

Rounding beforehand and adding up all of the distances gives us a perimeter of 18 units, which is remarkably close to the more precise approximation of 17.96 units. Given your options, 17.9 units would be the closest to the result we obtained here.

6 0
4 years ago
Read 2 more answers
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