Question

The data set below has a lower quartile of 13 and an upper quartile of 37.

Answer 1

Answer:

The correct option is 3.

Step-by-step explanation:

The first and third quartile of the data are 13 and 37.

The interquartile range is the difference between Q₃ and Q₁.

$\text{Interquartile Range}=Q_3-Q_1$

$\text{Interquartile Range}=37-13=24$

We have to find 1.5 (IQR),

$1.5\times \text{Interquartile Range}=1.5\times 24=36$

Now subtract 36 from Q₁ and add 36 in Q₃, if data lies outside the interval [Q₁-1.5(IQR),Q₃+1.5(IQR)] are called outliers.

$Q_1-36=13-36=-23$

$Q_3+36=37+36=73$

The outliers are the numbers which lies outside the range [-23,73]. Only 78 lies outside the range, therefore the correct option is 3.

Answer 2

Answer:

its C The greatest value, 78, is the only outlier

Step-by-step explanation: