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umka21 [38]
3 years ago
12

For a copper-silver alloy of composition 51 wt% Ag-49 wt% Cu and at 775˚C (1425˚F) (see Animated Figure 9.7) do the following: (

a) Determine the mass fractions of and phases. Mass fraction = [The tolerance is +/- 5.0%.] Mass fraction = [The tolerance is +/- 5.0%.] (b) Determine the mass fractions of primary and eutectic microconstituents. Mass fraction primary = [The tolerance is +/- 5.0%.] Mass fraction eutectic = [The tolerance is +/- 5.0%.] (c) Determine the mass fraction of eutectic . Mass fraction eutectic = [The tolerance is +/- 5.0%.]
Physics
1 answer:
77julia77 [94]3 years ago
8 0

And, finally, we are asked to compute the mass fraction of eutectic , We.  This quantity is simply the difference between the mass fractions of total  and primary  as

We = W – W' = 0.796 – 0.734 = 0.062

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Which of the following nuclei is most stable based on its binding energy?
Anettt [7]
We have that the most stable nuclei are the ones with the highest average binding energy. We see that Nitrogen has a mass number of 15 and that in this region of the graph average binding energy is low. Silver and Gold are along a line where there is a constant decline in average binding energy; silver has more than gold. However, we see that at the start of this decline, there is Fe 56. This region has the elements with the highest average binding energy; Nickel with a mass number of 58 is right there and thus it is the most stable nucleus out of the listed ones.
4 0
4 years ago
A horizontal force of 400 N is exerted on a 2.0-kg ball as it rotates (at
frutty [35]

Answer:

the speed of the ball is 10 m/s

Explanation:

Given;

magnitude of exerted force, F = 400 N

mass of the ball, m = 2 kg

radius of the circle, r = 0.5

The speed of the ball is calculated by applying centripetal force formula;

F = \frac{mv^2}{r} \\\\v^2 = \frac{Fr}{m}\\\\v = \sqrt{\frac{Fr}{m}}\\\\ v = \sqrt{\frac{400*0.5}{2}}\\\\v = 10 \ m/s

Therefore, the speed of the ball is 10 m/s

6 0
4 years ago
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The loudness of sound is determined by what?
baherus [9]
The amplitude of a sound<span> wave </span>determines<span> its </span>loudness<span> or volume. A larger amplitude means a louder </span>sound<span>, and a smaller amplitude means a softer </span><span>sound</span>
5 0
3 years ago
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An 800-kHz radio signal is detected at a point 8.5 km distant from a transmitter tower. The electric field amplitude of the sign
Temka [501]

Answer:

Explanation:

Given that,

Frequency of radio signal is

f = 800kHz = 800,000 Hz.

Distance from transmitter

d = 8.5km = 8500m

Electric field amplitude

E = 0.9 V/m

The average energy density can be calculated using

U_E = ½•ϵo•E²

Where ϵo = 8.85 × 10^-12 F/m

Then,

U_E = ½ × 8.85 × 10^-12 × 0.9²

U_E = 3.58 × 10^-12 J/m²

The average electromagnetic energy density is 3.58 × 10^-12 J/m²

6 0
4 years ago
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Suppose you have three identical metal spheres, AA, BB, and CC. Initially sphere AA carries a charge qq and the others are uncha
Sedaia [141]

Complete Question

Suppose you have three identical metal spheres, A, B, and C. Initially sphere A carries a charge q and the others are uncharged. Sphere A is brought in contact with sphere B, and then the two are separated. Spheres CC and BB are then brought in contact and separated. Finally spheres AA and CC are brought in contact and then separated. What is the final charge on the sphere B, in terms of q?

a. 3/8q

b. 1/4q

c. 3/4q

d. q

e. 5/8q

f. 1/3q

g.1/2q

h. 0

Answer:

   The correct option is b

Explanation:

From the question we are told that

          The charge carried by A is  q C

           The charge carried by B is 0 C

            The charge carried by C is 0 C

When A and B are brought close and then separated the charge carried by  A and B is mathematically evaluated as

                 \frac{ 0 + q}{2} =   \frac{q}{2}

When C and B are brought close and then separated the charge carried by  C and B  is mathematically evaluated as    

                    \frac{0 + \frac{q}{2} }{2}  = \frac{q}{4}

When C and A are brought close and then separated the charge carried by  C and A  is mathematically evaluated as  

                       \frac{\frac{q}{4} +  \frac{q}{2} }{2}   = \frac{3q}{8}

Looking at these calculation we can see that the charge carried by B is

        \frac{q}{4} C

8 0
3 years ago
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