3 years ago

Can I have the solution ?

Physics

1 answer:

valentinak56 [21]3 years ago

3 0

Hi there!

We know that since the object is at equilibrium, the net force must be equal to 0.

In the x-direction:

∑F = 0

Thus:

0 = 30 - OAsin(30) ⇒ Horizontal component of OA

Solve:

OAsin(30) = 30

OA (1/2) = 30

OA = 60 N

To find the weight, we must look at the y-direction.

The only forces in the y-direction are the tension's y-component and the weight, so:

0 = OAcos(30) - W

W = OAcos(30)

Plug in values:

W = 60 · √3/2

W = 30√3 N

The correct answer is B) 30√3, 60

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Can I have the solution ?​

Can I have the solution ?