Answer:
4 N to the right
Explanation:
For the object in this problem, we have 2 forces acting on it:
- A force of 2 N, to the right
- A force of 2 N, to the right
The two forces are in line: this means that the two vectors can be simply added by calculating their algebraic sum.
If we take right as positive direction, the two forces can be written as
F1 = +2 N
F2 = +2 N
So, the net force will be

And the positive sign means the direction is to the right.
Divide by 3.6
82/3.6 = 22.8 m/s
Answer:
<em>1,378.9ms²</em>
Explanation:
Given the following
Distance S = 70.6m
Time t = 0.32secs
Initial velocity = 0m/s
Required
Acceleration
Using the equation of motion
S = ut+1/2at²
Substitute
70.6 = 0+1/2a(0.32)²
70.6 = 0.0512a
a = 70.6/0.0512
a = 1,378.9
<em>Hence the acceleration is 1,378.9ms²</em>
I think it is A) but someone might need to double check that.