A Submerged Ball Part A A ball of mass mb and volume V is lowered on a string into a fluid of density Pi (Figure 1) Assume that
1 answer:
Answer:
T = mg - ×V×g
Explanation:
Here we have the mass of the ball is given as
The density of the fluid =
The volume of the ball = V
Acceleration due to gravity = g
According to Archimedes's principle, the upthrust = Weight of fluid displaced
Tension in string = T = weight of ball - upthrust
T = mg - ×V×g
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Answer:
K = 80.75 MeV
Explanation:
To calculate the kinetic energy of the antiproton we need to use conservation of energy:
<em>where : is the photon energy,
: are the rest energies of the proton and the antiproton, respectively, equals to m₀c²,
: are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>
Therefore the kinetic energy of the antiproton is:
<u>The proton mass is equal to the antiproton mass, so</u>:
Hence, the kinetic energy of the antiproton is 80.75 MeV.
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