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True [87]
3 years ago
5

5.32×10^5 solve it please need it by 12:00​

Mathematics
2 answers:
Neko [114]3 years ago
5 0

Answer:

<h2><em>532000</em></h2>

Step-by-step explanation:

5.32 × 10^5 =

532/100 × 100000 =

133/25 × 100000 =

532000

Gre4nikov [31]3 years ago
4 0

Answer:

532,000

Step-by-step explanation:

10^5= 100,000

100,000 x 5.32

Move the decimal place 5 spaces to the right.

It gives you 532,000

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What is the rate of heat transfer required to melt 1-ton of ice at 32 F in 24 hours?
LiRa [457]

Answer:

3865.74 J/s

Step-by-step explanation:

mass of ice, m = 1 ton = 1000 kg

time , t = 24 hours

latent heat of fusion of ice, L  = 334000 J/kg

Heat required to melt, H = m x L

where, m is the mass of ice and L be the latent heat of fusion

So, H = 1000 x 334000 = 334 xx 10^6 J

Rate of heat transfer = heat / time = \frac{334\times 10^{6}}{86400}

Rate of heat transfer = 3865.74 J/s

thus, the rate of heat transfer is 3865.74 J/s.

8 0
3 years ago
Daine received 300 votes in the election for student council president. which was 60% of the students who voted in the election.
Leokris [45]

Answer:

5

Step-by-step explanation:

i did 300 divided by 60%

6 0
3 years ago
Read 2 more answers
Can someone help me with all of these
vazorg [7]
7. = 29/9 0.6 terminating
8. = 301/20 0.75 terminating

6 0
3 years ago
Error 404.<br> Error 404.
Kitty [74]

Answer:

Error 404

Error 404

Error 404

Step-by-step explanation:

404

5 0
3 years ago
The absolute value function is written f(x) = |x|. It is composed of the lines y = x and y = -x. Its domain is the real numbers
Katena32 [7]
1.
no, there will never be a negative y-value.  <span>y= |x| will always be nonnegative. |x| can be distance x is from 0 and a distance can never be negative.

</span>2.
you can define it as
y = |x| = x if x ≥ 0, -x if x < 0

absolute value can be interpreted as a function that does not allow negative real numbers, forcing them to be positive (leaving 0 alone). if the input x is more than or equal 0, then x stays positive so there is no need to do anything: "x if x ≥ 0".
if the input is less than 0, then it is an negative number and needs a negative coefficient to negate the negative: "-x if x < 0"

example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does

if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.

for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does
4 0
3 years ago
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