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3 years ago

What is the solution to 1/3(s-2)=s+4

1 answer:

8 0

$\frac{1}{3} * (s-2)=s+4 \\ \\ \frac{s-2}{3}=s+4 \\ \\ s-2=3(s+4) \\ \\ s-2= 3s+12 \\ \\ s-3s=12+2 \\ \\ -2s= 14 \\ \\ \boxed{s= -\frac{14}{2}=-7}}$

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How do u write 5,823 in scientific notation

Alex73 [517]

<span>5.823 x 103 i hope it right ???</span>

4 0

3 years ago

Read 2 more answers

Use the recursive formula to answer the question.

scZoUnD [109]

You know a1.
So find a2, a3, and so on until a7.

a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.

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3 years ago

Marti is filling a 10– inch diameter ball with sand to make a medicine ball that can be used for exercising. To determine if the

Mice21 [21]

Answer:

Option A. $30\ pounds$

Step-by-step explanation:

step 1

Find the volume of the sphere ( medicine ball)

The volume is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=10/2=5\ in$ ----> the radius is half the diameter

Convert inches to feet

Remember that

1 ft=12 in

$r=5\ in=5/12\ ft$

assume

$\pi=3.14$

substitute

$V=\frac{4}{3}(3.14)(5/12)^{3}$

$V=0.3029\ ft^{3}$

step 2

Find the weight of the ball

Multiply the volume in cubic foot by 100

$0.3029*100=30.29\ pounds$

Round to the nearest pound

$30.29=30\ pounds$

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3 years ago

Preform the indicated operation.<br> 4/11 ÷ 4/9

BartSMP [9]

Answer:

0/8

Step-by-step explanation: i tried my best

4 0

2 years ago

Read 2 more answers

Jessica is measuring two line segments. The first line segment is 30 centimeters long. The second line segment is 500 millimeter

Zolol [24]

Answer:

800 mm or 80 cm

Step-by-step explanation:

We are given that Jessica is measuring two line segments.

Length of first line segment =30 cm

Length of second line segment=300 mm

We have to find that Length of two line segments together

We know that 1 cm =10 mm

Length of firs line segment =

Length of two line segments together=500+300=800 mm=

Hence, the length of two line segments together=800 mm=80 cm

Read more on Brainly.com - brainly.com/question/544258#readmore

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3 years ago