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4 years ago

William can pack 60 toys in 4 hours. find the unit rate with which he packs toys

Mathematics

1 answer:

RideAnS [48]4 years ago

3 0

William can pack 15 toys per hour

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Convert the given amount to the given unit.<br> 6.5 lb; ounces<br> 6.5 lb =<br> ounces

Aneli [31]

Answer:

the answer is 104

Step-by-step explanation:

1= 16

6= 96

0,5=8

5 0

4 years ago

1.3y + 5.2= -3.9x<br> Can someone help me?

slamgirl [31]

Answer.

Step-by-step explanation:

6 0

3 years ago

Simplify the following: 3(-3 + 5x) -1 (4 - 4x)

Gnesinka [82]

3(-3 + 5x) -1 (4 - 4x)

Simplify each term by first using the distributive property with each set of parenthesis:

3*-3 + 3*5x - 1*4 -1* -4x

Now do the multiplications:

-9 + 15x -4 + 4x

Combine like terms

15x +4x - 9 -4

19x - 13

8 0

3 years ago

Divide 88,800 By 100 Explain the shift of the digits and the change in the value of each digit

ololo11 [35]

88,800÷100=888 because when you are dividing by multiples of 10, the place value always move over to the right depending on how many digits there are.

6 0

4 years ago

Suppose that a function f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence

Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

$\lim_{x \to c} \frac{x^2-cx}{(x-c)}$

We can simplify it

$\lim_{x \to c} \frac{x(x-c)}{(x-c)}$

$=\lim_{x \to c} x$

$=c$

so, we can see that limit exist and it's value defined

case-2:

$\lim_{x \to c} \frac{1}{(x-c)}$

Left limit is

$\lim_{x \to c-} \frac{1}{(x-c)}$

$=-\infty$

Right Limit is

$\lim_{x \to c+} \frac{1}{(x-c)}$

$=+\infty$

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0

3 years ago