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2 years ago

Relation between glancing and angle of deviation

Chemistry

1 answer:

shtirl [24]2 years ago

5 0

Answer:

the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.

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Which of the following is the correct name for the compound mgbr2? magnesium bromate magnesium bromide magnesium dibromide magne

Sergeeva-Olga [200]

Correct answer is magnesium bromide. This is an ionic compound with metal forming a positive ion - K+ and halogen forming a negative ion - Br-. When group 7 element form ions they have a suffix -ide. Bromine is the element and when it forms a negative ion bromine is called bromide with the suffix.
Magnesium gives 2 electrons and bromine can take only 1 electron, therefore 2 bromine atoms are needed. Therefore magnesium forms ionic bonds with 2 bromine atoms.
The compound is called magnesium bromide

6 0

3 years ago

What is the acceleration of the object’s motion? 0.5 m/s2 -0.5 m/s2 2 m/s2 -2 m/s2

djverab [1.8K]

Answer: -2m/s2

Explanation:

Using the following equation ; acceleration = Change in velocity / time

i.e a = v - u / t

where 'a' = acceleration

v = final velocity

u = initial velocity

t = time

Therefore; from the graph we have acceleration to be, 0 - 6m/s / 3s = -2m/s2

5 0

3 years ago

Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2

lapo4ka [179]

Answer: Concentration of $CO$ = 0.328 M

Concentration of $Cl_2$ = 0.328 M

Concentration of $COCl_2$ = 0.532 M

Explanation:

Moles of $CO$ and $Cl_2$ = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of $CO$ and $Cl_2$ = $\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M$

The given balanced equilibrium reaction is,

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.860M 0.860M 0

At eqm. conc. (0.860-x) M (0.860-x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get :

$4.95=\frac{x}{(0.860-x)^2}$

By solving the term 'x', we get :

x = 0.532 M

Thus, the concentrations of $CO,Cl_2\text{ and }COCl_2$ at equilibrium are :

Concentration of $CO$ = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of $Cl_2$ = (0.860-x) M = (0.860-0.532) M = 0.328 M

Concentration of $COCl_2$ = x M = 0.532 M

3 0

2 years ago

Calculate the work (kJ) done during a reaction in which the internal volume contracts from 85 L to 12 L against an outside press

butalik [34]

Answer:

The work done on the system is 17.75_KJ

Explanation:

To solve this question we need to know the required equations from the given variables, thus

Initial volume = 85L

Final volume = 12L

External pressure = 2.4 atm.

work done = - PΔV

2.4×(85-12) = 175.2L×atm

Converting from L•atm to KJ is given by

1 L•atm = 0.1013 kJ

(175.2 L•atm) * (0.1013 kJ / 1 L•atm)

= 17.75 kJ

The work done on the system is 17.75_KJ

5 0

3 years ago

Why must the line of origin be drawn in pencil instead of pen on the chromatography strip?

Kruka [31]

Answer:

Because if you use pen, your chromatography will separate also the colors of the pen and not just your sample.

Explanation:

The pencil since is carbon as simple element, is solid and is not dissolved in solvents like commonly are used in paper chromatography, it will not interrupt the separation of the compounds in your mixture, otherwise, your results will be confuse because you are not sure if the spots that you observe is due to the ink pen or due to the mixture that you want to separate.

5 0

3 years ago

Relation between glancing and angle of deviation​

Relation between glancing and angle of deviation