True, they exist in exactly one plane
Answer:
Step-by-step explanation:
Degree of quadratic equation is 2
So, y = (x + 2)² - 6 ; y = x² - 4x + 2 & y = -(x -2)² + 5 are quadratic equation
(a + b)² = a² + 2ab + b²
y = (x + 2)² - 6
y = x² + 2*x*2 + 2² -6
y= x² + 4x + 4 -6
y= x² + 4x - 2
Degree = 2
y = -(x - 2)² + 5
y = -[ x² - 2*x*2 + 2²] + 5
y = -[x² - 4x + 4)+5
y = -x² + 4x - 4 + 5
y = -x² + 4x + 1
Degree = 2
Answer:
d
Step-by-step explanation:
