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iren2701 [21]
3 years ago
5

A translation or rotation is a composition of two _____

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0

<u>Answer:</u>

Reflections


<u>Explanation:</u>

<u>1- For translation:</u>

A translation can be a composition of a reflection as it can composed by two reflections over parallel lines.

These lines should be separated by a distance equal to half the distance of translation


<u>2- For rotation:</u>

A rotation can be a composition of a reflection as it can composed by two reflections over non-parallel lines.

These two non-parallel lines should intersect at the point representing the center of rotation


Hope this helps :)

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10. 10. If AB bisects CAF, and m&lt;EAF = 72°,<br>then the m&lt;BAF =​
never [62]

The measure of ∠BAF is 54°.

Solution:

DF and CE are intersecting lines.

m∠EAF = 72° and AB bisects ∠CAF.

∠EAF and ∠DAC are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

∠DAC ≅ ∠EAF

m∠DAC = 72°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠DAE + m∠EAF = 180°

m∠DAE + 72° = 180°

Subtract 72° from both sides.

m∠DAE = 108°

∠CAF and ∠DAE are vertically opposite angles.

⇒ m∠CAF = m∠DAE

⇒ m∠CAF = 108°

AB bisects ∠CAF means ∠CAB = ∠BAF

m∠CAB + m∠BAF = 108°

m∠BAF + m∠BAF = 108°

2 m∠BAF = 108°

Divide by 2 on both sides, we get

m∠BAF = 54°

Hence the measure of ∠BAF is 54°.

4 0
3 years ago
Order these numbers least to greatest!<br> Pls help!! Will mark u brainliest!
AnnyKZ [126]
Ok so its 50, -7.6, -7.64. then -157 divided by 20
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3 years ago
the art teacher is sending home a total of 3,150 projects before winter break if each of her 150 students had the same number of
Alenkinab [10]

Answer:

21 projects each

Step-by-step explanation:

3150 ÷150

4 0
3 years ago
How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

28 = k\cdot 10^2+m\cdot 10+n\\21=k\cdot 20^2+m\cdot 20+n\\16=k\cdot 30^2+m\cdot 30+n

Subtracting each equation from the one after gives

-7=300k+10m\\-5=500k+10m

Subtracting the first of these equations from the second gives

2=200k\\\\k=\dfrac{2}{200}=0.01

Using the next previous equation, we can find m.

-5=500\cdot 0.01+10m\\\\m=\dfrac{-10}{10}=-1

Then from the first equation

[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]

There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

b) At 150 kph, the cost is predicted to be

... c = 0.01·150² -150 +37 = 112 . . . cents/km

c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.

d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.

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3 years ago
Two boats start their journey from the same point A and travel along directions AC and AD, as shown below
adell [148]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
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