Don't need an explanation! Just correct answers please! I'm so stressed :/

Mathematics

2 answers:

Mrac [35]3 years ago

6 0

Y=mx you just multiply m and x :)
3
0
-3
-6

Julli [10]3 years ago

6 0

We know, the principle equation of line,
y = mx + c
when, x = -1, y = 3, m = -3, c =?
3 = (-1)(-3) + c
c = 3 - 3 = 0

When, x = 0, y = (-3)(0) = 0
x = 1, y = (-3)(1) = -3
x = 2, y = (-3)(2) = -6

In short, Your Answers would be 0, -3, -6

Hope this helps!

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Which description of the vector shown is correct ?

BartSMP [9]

Answer:

(B) The magnitude is 7sqrt2, and the direction angle is approximately 135 degrees.

Step-by-step explanation:

From the figure, the coordinate of the tail of the vector,

$(x_1,y_1)=(3,-6).$

The coordinate of the head of the vector,

$(x_2,y_2)=(-4,1).$

The magnitude of a vector is the length between the head and tail of the vector.

By using the distance formula,

the magnitude of the vector $= \sqrt{(1-(-6))^2+(-4-3)^2}$

$=\sqrt{(7^2+(-7)^2}\\\\=\sqrt{98}\\\\=7\sqrt{2}$

Now, let $\theta$ be the angle made by the vector with the positive direction of the x-axis, so

$\tan\theta = \frac{y_2-y_1}{x_2-x_1}\\\\\Rightarrow \tan\theta = \frac{1-(-6)}{-4-3}=\frac{7}{-7}=-1 \\\\\Rightarrow \theta = \tan^{-1}(-1) \\\\\Rightarrow \theta =\pi- \tan^{-1}1 \\\\\Rightarrow \theta = \pi-\frac{\pi}{4} \\\\\Rightarrow \theta =\frac{3\pi}{4} \\\\\Rightarrow \theta = 135 ^{\circ}.$