Given the position function
<em>s(t)</em> = 3 - cos(<em>t</em> )
differentiate once to get the velocity, and twice to get the acceleration:
<em>v(t)</em> = <em>s'(t)</em> = sin(<em>t </em>) → <em>v</em> (4.3 s) ≈ -0.92
<em>a(t)</em> = <em>s''(t)</em> = <em>v'(t)</em> = cos(<em>t </em>) → <em>a</em> (4.3 s) ≈ -0.40
The acceleration is negative, so the particle is slowing down.
It makes a rectangle if graphed.
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Answer:
Step-by-step explanation:
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