The force of gravity will decrease.
More the distance between the objects, less the force of gravity between them.
They are inversely related.
Hope this help :)
Answer:
Explanation:
Given that,
Mass of first car
M1= 328kg
The car is moving in positive direction of x axis with velocity
U1 = 19.1m/s
Velocity of second car
U2 = 13m/s, in the same direction as the first car..
Mass of second car
M2 = 790kg
Velocity of second car after collision
V2 = 15.1 m/s
Velocity of first car after collision
V1 =?
This is an elastic collision,
And using the conservation of momentum principle
Momentum before collision is equal to momentum after collision
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The velocity of the first car after collision is 14.04 m/s
Answer:
Explanation:
The formula S=(at^2)/2 will be used during the entire explanation.
1. 4 = (2t^2)/2
t = 2 s.
V = at = 2 * 2 = 4 m/s
2. 8 = (2t^2)/2
t = 2.8 s
iii. 2s
iv. 2.8 - 2 = 0.8s
Hope you understand)
Answer:
B is the answer
Explanation:
When A is divided by 7x, it multiplies to0.81
