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KonstantinChe [14]
3 years ago
5

A car accelerates uniformly from 18km per hour to 36km per hour in 10 seconds . Calculate the acceleration in km/h^2

Physics
2 answers:
Andreas93 [3]3 years ago
6 0

Answer:Acceleration = Change in Velocity/Time

Change in Velocity = 36-18 = 18 km/h=5 m/s

Time= 5 Seconds

Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2

u=18 km/h=5 m/s

t=5 s

a=1 m/s2

s= (5*5)+(1/2*1*5*5)

s=25+12.5 i.e., s=37.5 m

Hope you are clear with my explanations

grin007 [14]3 years ago
5 0
To change second to hour you need to divide by 60 because 1 minute equal to 60 seconds then divide again by 60 because you want your answer in km/h right? So you will get 360.

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The height need to change by 4 to double the final velocity.

<h3>Final velocity of the object</h3>

The final velocity of an object during a free fall is related to maximum height of fall as given the equation below.

v = √2gh

v² = 2gh

v²/h = 2g

v₁²/h₁ = v₂²/h₂

when v₂ = 2v₁, change in height is calculated as;

h₂ = h₁v₂²/v₁²

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h₂ = 4h₁

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4 0
2 years ago
When using a cell phone, a(n) ________ converter chip changes your voice's sound waves into digital signals.
Nuetrik [128]

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3 years ago
Which equation best describes the law of conservation of momentum?
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8 0
3 years ago
Read 2 more answers
a runner covers the last straight stretch of the race in 4 s. durning that time, he speeds up from 5 m/s to 9m/s what is the run
Sergio039 [100]

Answer:

The runner's acceleration was 1\ m/s^2

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:

\displaystyle a=\frac{9-5}{4}

\displaystyle a=\frac{4}{4}=1

The runner's acceleration was 1\ m/s^2

5 0
3 years ago
A hot air balloon lifts 50 meters vertically into the air and then comes back down. What are the displacement and distance of th
Marysya12 [62]

Given that a hot air balloon lifts 50 meters vertically into the air and then comes back down.

The displacement is the distance covered in a specific direction.

When the balloon is going up, the displacement is positive. and when the balloon is coming down, the displacement is negative.

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The distance is a measurement of length between to different points or position.

For distance, there is no need to consider direction. There is no consideration for positive or negative signs

While the distance = 50 + 50 = 100 meters

Therefore, the correct answer is C

That is, The displacement is zero and the distance is 100 meters

Learn more on ; brainly.com/question/24662122

4 0
3 years ago
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