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3 years ago

On a small planet, an astronaut uses a vertical

Physics

2 answers:

Salsk061 [2.6K]3 years ago

8 0

Answer:

<h2>2.00 N/kg approximately.</h2>

Explanation:

A gravitational flied is defined as the quotient between the gravitational force and the mass:

$g=\frac{F}{m}$

Replacing all given values, we have:

$g=\frac{175N}{97.6kg}\\ g=1.96\frac{m}{s^{2} }$

Therefore, the gravitational filed is approximately 2.00 N/kg.

sleet_krkn [62]3 years ago

6 0

Constant velocity means the netto force = 0, therefore F(gravity) = F(astronaut).
175N divided by 87,5kg = 2.00kg/N

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Ch 14:42

Alisiya [41]

Answer:

1000m3

Explanation:

12000=mass*gravity, considerinh gravity 10

12000=mass*10 then mass=1200Kg

With density 1.2Kg/m3

1.2Kg ... 1m3

1200Kg ... 1000m3

End

4 0

3 years ago

A 68 kg deer has a momentum of 952 kg∙m/s. What is its velocity?

Gwar [14]

All we need to do is divide the momentum and weight to find the velocity:

v = m / w

Solve using the values we are given.

v = 952/68 = 14 m/s

Best of Luck!

5 0

3 years ago

How many 90-W, 120-V light bulbs can be connected to a 20-A, 120-V circuit without tripping the circuit breaker? (Note: This des

spayn [35]

Answer:

Explanation:

Total power of the circuit

P = V × I = 120 × 20 = 2400 W

Power of each bulb = 90 W

Number of bulbs which work without tripping

N = power of circuit / power of each bulb

N = 2400 / 90

N = 26.66

Number of bulbs should be integer so the number of bulbs be 26.

8 0

3 years ago

Ohm's Law for electrical circuits is stated VequalsRI, where V is a constant voltage, R is the resistance in ohms and I is the

Annette [7]

Answer:

The resistance interval is $R = 1.8 \pm 0.037$

Explanation:

From the question we are told that

The voltage is V = 9 V

The current is $I = 5 \pm 0.1$

The maximum current would be

$I_{max} = 5 + 0.1 = 5.1 \ A$

The minimum current would be

$I_{min} = 5 - 0.1 = 4.9 \ A$

The maximum resistance is

$R_max = \frac{V}{I_{min}}$

$R_max = \frac{9}{4.9}$

$R_max = 1.837 \Omega$

The minimum resistance is

$R_{min} = \frac{V}{I_{max}}$

$R_{min} = \frac{9}{5.1}$

$R_{min} = 1.765 \Omega$

and $R = \frac{9}{5} = 1.8 \Omega$

The interval R lies is

$R = 1.8 \pm 0.037$

4 0

3 years ago

A concrete column has a diameter of 380 mm and a length of 2.6 m . if the density (mass/volume) of concrete is 2.45 mg/m3, deter

grigory [225]

The volume of the column is

(π) · (r²) · (length) =

(π) · (0.19 meter)² · (2.6 meters) =

(π) · (0.036 m²) · (2.6 m) =

0.294 m³ .

The density is 2,450 kg/m³ (VERY very dense, heavy concrete)

so the weight of the column is (mass)·(gravity) or

(density) · (volume) · (gravity) =

(2,450 kg/m³) · (0.294 m³) · (9.81 m/s²) =

(2,450 · 0.294 · 9.81) (kg · m³· m) / (m³ · s²) =

7,066 kg-m/s² = 7,066 Newtons .

But 9.81 Newtons = 2.20462 pounds on Earth (the weight of 1 kilogram of mass), so we have

(7,066 N) · (2.205 pound/9.81 N) =

(7,066 · 2.205 / 9.81) pounds =

1,588 pounds .

5 0

3 years ago