Answer:
- Total surface area of cylinderal can is 150.8 cm²
<u>Step-by-step </u><u>explanation</u><u>:</u><u> </u>
Given that a cylinderal can has base with a diameter of 6 cm and its height measures 5 cm.
So,
Radius = Diameter/2 = 6/2 = 3 cm
We know that,
- TSA of cylinder = 2πr(h + r)
Substituting required values:
➝ TSA = 2 × 22/7 × 3(5 + 3)
➝ TSA = 44/ 7 × 3 × 8
➝ TSA = 1056/7
➝ TSA = 150.8 cm²
Hence,
- <u>Total </u><u>surface </u><u>area </u><u>of </u><u>cylinderal</u><u> </u><u>can </u><u>is </u><u>1</u><u>5</u><u>0</u><u>.</u><u>8</u><u> </u><u>cm²</u>
Answer:
Do you have the pictures of the graphs?
Step-by-step explanation:
Multiply by 1.12 or 112%, to get 12% of a given number.
Consider ΔABP and ΔCBP. They have:
1. AB ≅ BC (by definition of kite);
2. BP ≅ BP (by reflexive property);
3. BP ⊥ AC (by definition of kite).
Then these two triangles are congruent be HL theorem.
Corresponding parts of congruent triangles are congruent (by definition of congruent triangles), then the correct choice for step 5 is A.
