Answer:
A. 
B. 
C. 
D. 
Explanation:
Hello.
In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

Thus, we proceed as follows:
A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

Best regards.
Acylhomoserine lactones used in quorum sensing regulate their own synthesis by an autoinduction system.
- Numerous bacteria use acyl homoserine lactones (acyl-HSLs), significant intercellular signaling molecules, to track the density of their population for quorum-sensing control of gene expression. The LuxI family of proteins produces the signals in question.
- A lot of proteobacteria use quorum-sensing signals from acyl-homoserine lactones.
- Cells create a baseline amount of signal at low population densities, and when enough signal has accumulated in the environment, it binds to its receptor and activates quorum-sensing-dependent genes.
learn more about Acylhomoserine here: brainly.com/question/14452252
#SPJ4
Answer:
c
Explanation:
The answer is c I think
Am not too sure but I think
Answer:
what's this bae ? Thanks!❤︎ت︎
Answer:
Salt
Explanation:
Ocean water has salt in it unlike lakes and rivers