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Vladimir79 [104]
3 years ago
9

Determine whether or not the function r(x) =x^2-2 is one -to-one

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer:

The function is not one-to-one

Step-by-step explanation:

This is a quadratic function.

f(x)=x^2-2

A function is one-to-one

\text{if } f(x_1)=f(x_2) \Leftrightarrow x_1=x_2

The function given is not one-to-one because there are values of the input x, which leads to the same output.

For example.

y=f(2)=2^2-2=\boxed{2}

y=f(-2)=(-2)^2-2=\boxed{2}

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Nikhil, Davina and Sid share a tin of celebrations amongst themselves in the ratio of 8:12:20 respectively.
Sav [38]

Answer:

160

Step-by-step explanation:

n : d : s

8 : 12 : 20

davina = 48 sweets

48/12 = 4

8 + 12 + 20 = 40

40 x 4 = 160 sweets total

5 0
3 years ago
Simplify (11 + 5i)(11 - 51)
Ede4ka [16]

Answer:

 (146 +  0i)

Step-by-step explanation:

(11+5i)(11-5i)

The formula is :

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and since  i^2 = -1  it can be written as :

ax - by + (ay + bx) i

( 11 +  5i) • ( 11 -  5i) =

 (146 +  0i)

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3 years ago
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Step-by-step explanation:

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3 years ago
Center (-15,11) radius 2
kodGreya [7K]

Answer:

(x+15)^2+(y-11)^2=4

Step-by-step explanation:

<u><em>The question is</em></u>

How do you write an equation for a circle with center (-15,11) and radius 2?

we know that

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Step-by-step explanation:

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