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3 years ago

Please someone help what’s to answer to f(3)=2 + g(5)=-17

Mathematics

1 answer:

Alex777 [14]3 years ago

5 0

Answer:

5 g - 2.

Step-by-step explanation:77217, Solve for g, 19*23=17g, 19⋅23=17g 19 ⋅ 23 = 17 g ... 77235, Solve for g, g^-1(7)=3, g−1(7)=3 g - 1 ( 7 ) = 3 ... 77244, Solve for g, (g-2)/(g+10)=(g-4)/(g+5), g−2g+10=g−4g+5 g - 2 g + 10 = g - 4 g + 5 ... 77266, Solve for g, (7g-21)/3-(2g-7)/4+1=5g-2, 7g−213−2g−74+1=5g−2 7 g - 21 3 - 2 g - 7 4 + 1 = 5 g - 2.

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Find the area of this shape

Korolek [52]

Answer:

1496π square meters

Step-by-step explanation:

A=2πrh+2πr²

=2π(17)(27)+2π(17)²

= 918π + 578π

=1496π

6 0

3 years ago

10 Jenny has 12 marbles.

liraira [26]

Answer:

620

Step-by-step explanation:

12-1=11

11x50

1x70

add the two totals and you should get 620

Hope this helps!

5 0

3 years ago

Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...

rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

$x_n = a n^4 + b n^3 + c n^2 + d n + e$

From the given known values of the sequence, we have

$\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}$

Solving the system yields coefficients

$a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4$

so that the n-th term in the sequence might be

$\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}$

Then the next few terms in the sequence could very well be

$\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}$

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of $\{x_n\}$ eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of $\{x_n\}$ by $\Delta^{k}\{x_n\}$ . Then

• 1st-order differences:

$\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}$

• 2nd-order differences:

$\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}$

• 3rd-order differences:

$\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}$

• 4th-order differences:

$\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}$

From here I made the assumption that $\Delta^4\{x_n\}$ is the constant sequence {15, 15, 15, …}. This implies $\Delta^3\{x_n\}$ forms an arithmetic/linear sequence, which implies $\Delta^2\{x_n\}$ forms a quadratic sequence, and so on up $\{x_n\}$ forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.

5 0

2 years ago

PLEASE HELP I WILL GIVE 100 POINTS!!!!!!!!Given rectangle ABCD ~ HGFE , what is the length of HG ?

never [62]

Since rectangle ABCD is similar to HGFE, the ratios of the lengths of their corresponding sides are equal. We can infer form our picture that AD is corresponding to EH and DC is corresponding to HG, so lets find the ratios of those corresponding sides and establish a proportion to find the length of HG:
$\frac{AD}{EH} = \frac{DC}{HG}$
We know that $AD=45$ , $EH=27$ , and $DC=15$ , so lets replace those values in our proportion:
$\frac{45}{27} = \frac{15}{HG}$
$HG= \frac{27*15}{45}$
$HG= \frac{405}{45}$
$HG=9$

We can conclude that the length of the segment HG is 9.

8 0

3 years ago

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Martin has a piece of purple yarn that is 3 1/2 inches long he has a piece of yellow yarn that is 3 5/6 inches Long how much lon

sweet-ann [11.9K]

Answer:

2 1/3 longer

Step-by-step explanation:

yw ;)

5 0

2 years ago

Read 2 more answers