Answer:
4400 ml
Explanation:
80.0 g Na and 20.0 g N2.
This means the limiting reactant determines the maximum mass of the product formed.
6.66 mol
(atm x L) ÷ (0.0821 x K)
(0.875 x 250) ÷ (0.0821 x 400)
=6.66108