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3 years ago

How many grams of water will form if 10.54 g H2 react with 95.10 g O2?

Chemistry

2 answers:

sergiy2304 [10]3 years ago

5 0

Answer:

94.0 g H2O

Explanation:

uranmaximum [27]3 years ago

5 0

Answer:94.0 g H2O

Explanation:

2H2 + O2 --> 2H2O

The

question asked me how many grams of water will form if 10.54 g H2 react with 95.10 g O2.

The correct answer was 94.0g of H2O I got from

10.54g H2 * 1 mol H2/2.02 g/mol H2 * 2 mol H2O/2 mol H2 = 5.22 mol H2O

95.10g O2* 1 mol O2/32 g/mol O2 * 2 mol H2O/1 mol O2 = 5.94 mol H2O

The limiting reactant is 5.22 mol, which 5.22 mol H2O * 18.01 g/mol H2O = 94.0g H2O.

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Answer: The molality of the solution is 0.1 m.

Explanation:

To calculate the molality of solution, we use the equation:

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Where,

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2 years ago

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2 years ago

A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui

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Answer:

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Explanation:

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Volume displaced = 0.002346 m³

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The free body diagram of the sphere is shown in image.

According to image:

$mg=\rho\times gV+T$

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Tension force = 26 N

Applying in the equation to find the density of the liquid as:

$6.1\times 9.81=\rho\times 9.81\times 0.002346+26$

$33.841=\rho\times 9.81\times 0.002346$

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