Given what we know, we can confirm that in Reno, NV, the angle of the Sun is lower during the winter months and <u>higher </u>in the <u>sky </u>during the summer.
<h3>How can we know this?</h3>
We can know this about Reno, NV, given that it is irrelevant where we placed this question. the answer will be the same all across the world. It has to do with the way the Earth orbits the Sun as well as the tilt of the Earth. This causes the Sun to be higher in the sky during summer and lower in the winter months.
Therefore, we can confirm that the angle of the Sun is lower during the winter months and higher in the sky during the summer, both in Reno, NV and everywhere else.
To learn more about The Earth's orbit visit:
brainly.com/question/15022652?referrer=searchResults
Answer:
There are 29.4 grams of oxygen in the container
Explanation:
<u>Step 1: </u>Data given
Volume = 20.0 L
Pressure = 845 mmHg
Temperature = 22.0 °C
Molar mass of O2 = 32 g/mol
<u>Step 2:</u> Ideal gas law
p*V = n*R*T
⇒ p = the pressure of the gas = 845 mmHg = 1.11184
⇒ V = the volume of the gas = 20.0 L
⇒ n = the number of moles = TO BE DETERMINED
⇒R = the gasconstant = 0.08206 L*atm/K*mol
⇒ T = the temperature = 22°C + 273 = 295 Kelvin
n = (p*V)/(R*T)
n = (1.11184*20.0)/(0.08206*295)
n = 0.9186 moles
<u>Step 3:</u> Calculate mass of NO2
Mass of O2 = Moles O2 * Molar mass O2
Mass of O2 = 0.9186 moles * 32 g/mol
Mass of O2 = 29.4 grams
There are 29.4 grams of oxygen in the container
Yes because an organic compound is any member of large class of gaseous liquid or solid chemical compound whose molecules contains carbon
Answer:
1.53 L
Explanation:
Step 1: Given data
- Mass of oxygen (m): 11.2 g
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
11.2 g × (1 mol/32.00 g) = 0.350 mol
Step 3: Calculate the volume of oxygen
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm
V = 1.53 L
Answer:
76.0%
Explanation:
Let's consider the following reaction.
CaCO₃(s) ⇄ CaO(s) + CO₂(g)
At equilibrium, the equilibrium constant Kp is:
Kp = 1.16 = pCO₂ ⇒ pCO₂ = 1.16 atm
We can calculate the moles of CO₂ at equilibrium using the ideal gas equation.
From the balanced equation, we know that 1 mole of CO₂ is produced by 1 mole of CaCO₃. Taking into account that the molar mass of CaCO₃ is 100.09 g/mol, the mass of CaCO₃ that reacted is:
The percentage by mass of the CaCO₃ that reacted to reach equilibrium is:
