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Rzqust [24]
3 years ago
14

How many grams of water will form if 10.54 g H2 react with 95.10 g O2?

Chemistry
2 answers:
sergiy2304 [10]3 years ago
5 0

Answer:

94.0 g H2O

Explanation:

uranmaximum [27]3 years ago
5 0

Answer:94.0 g H2O

Explanation:

2H2 + O2 --> 2H2O

The

question asked me how many grams of water will form if 10.54 g H2 react with 95.10 g O2.

The correct answer was 94.0g of H2O I got from

10.54g H2 * 1 mol H2/2.02 g/mol H2 * 2 mol H2O/2 mol H2 = 5.22 mol H2O

95.10g O2* 1 mol O2/32 g/mol O2 * 2 mol H2O/1 mol O2 = 5.94 mol H2O

The limiting reactant is 5.22 mol, which 5.22 mol H2O * 18.01 g/mol H2O = 94.0g H2O.

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Which of the following are density labels?
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Answer:

Kg/L , g/mL

Explanation:

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7 0
3 years ago
5. Uranium has three common isotopes. If the abundance of 2U which has an atomic mass of 233.878 amu is 0.01%, the
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Uranium has three common isotopes. The average atomic mass of uranium is 23.7 u/atom.

<h3>What are isotopes?</h3>

Isotopes are similar elements that have a different number of protons.

Uranium has three isotopes

The abundance of 2U has an atomic mass of 233.878 is 0.01%

The abundance of U has a mass of 234.892 amu is 0.71%

The **U has an atomic mass of 237.911 amu is 99.28%

Let's assume we have 10 000 atoms of Uranium

Mass of the 0.01 atoms = 0.01 x 233.878 = 2.33878

Mass of the 0.71 atoms =  0.71 x 234.892 = 166.773

Mass of the 99.28 atoms = 99.28 x 237.911 = 23,619.80

2.33878 + 166.773 + 23,619.80 = 23,788.8

23,788.8 / 1000 = 23.7 u/atom

Thus, the average atomic mass of uranium is 23.7 u/atom.

To learn more about average atomic mass, refer to the link:

brainly.com/question/12971445

#SPJ1

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1 year ago
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