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3 years ago

How many grams of water will form if 10.54 g H2 react with 95.10 g O2?

Chemistry

2 answers:

sergiy2304 [10]3 years ago

5 0

Answer:

94.0 g H2O

Explanation:

uranmaximum [27]3 years ago

5 0

Answer:94.0 g H2O

Explanation:

2H2 + O2 --> 2H2O

The

question asked me how many grams of water will form if 10.54 g H2 react with 95.10 g O2.

The correct answer was 94.0g of H2O I got from

10.54g H2 * 1 mol H2/2.02 g/mol H2 * 2 mol H2O/2 mol H2 = 5.22 mol H2O

95.10g O2* 1 mol O2/32 g/mol O2 * 2 mol H2O/1 mol O2 = 5.94 mol H2O

The limiting reactant is 5.22 mol, which 5.22 mol H2O * 18.01 g/mol H2O = 94.0g H2O.

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$-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K$

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