Protons are positively charged particles and neutrons have no charge. On the other hand, electrons are negatively charged specie
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27) Partial pressure of oxygen: 57.8 kPa
29) Final volume: 80 mL
30) Final volume: 8987 L
31) Due to property of water of being polar, ice floats on water
Explanation:
27)
In a mixture of gases, the total pressure of the mixture is the sum of the partial pressures:
In this problem, the mixture contains 3 gases (helium, carbon dioxide and oxygen). We know that the total pressure is
We also know the partial pressures of helium and carbon dioxide:
The total pressure can be written as
where is the partial pressure of oxygen. Therefore, we find
29)
Assuming that the pressure of the gas is constant, we can apply Charle's law, which states that:
"For an ideal gas at constant pressure, the volume of the gas is proportional to its absolute temperature"
Mathematically,
where
V is the volume of the gas
T is the Kelvin temperature
We can re-write it as
Here we have:
(initial volume)
is the initial temperature
is the final temperature
Solving for V2, we find the final volume:
30)
For this problem, we can use the equation of state for ideal gases, which can be written as
where in this problem:
is the initial pressure
is the initial volume
is the initial temperature
is the final pressure
is the final temperature
And solving for V2, we find the final volume of the balloon:
31)
A molecule of water consists of two atoms hydrogen bond with an atom of oxygen () in a covalent bond.
While the molecul of water is overall neutral, due to the higher electronegativity of the oxygen atom, electrons are slightly shifted towards the oxygen atom; as a result, there is a slightly positive charge on the hydrogen side, and a slightly negative charge on the oxygen side (so, the molecules is said to be polar).
As a consequence, molecules of water attract each other, forming the so-called "hydrogen bonds".
One direct consequence of the polarity of water is that ice floats on liquid water.
Normally, for every substance on Earth, the solid state is more dense than the liquid state. However, this is not true for water, because ice is less dense than liquid water.
This is due to the polarity of water. In fact, when the temperature of water is decreased to freezing point and water becomes ice, the hydrogen bondings "force" the molecules to arrange in a lattice structure, so that the molecules become more spaced when they turn into solid state. As a result, ice occupies more volume than water, and therefore it is less dense, being able to float on water.
Learn more about ideal gases:
#LearnwithBrainly
The coefficients in the order CH₄, O₂, CO₂, and H₂O, are 1,2,1,2
The equation becomes:
CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)
<h3><em>Further explanation</em></h3>
Complete combustion of hydrocarbon with oxygen will be obtained by CO₂ and H₂O compounds.
If O is insufficient there will be incomplete combustion produced by CO and H and O
Hydrocarbon combustion reactions (specifically alkanes)
Equalization of chemical reaction equations can be done using variables.
Steps in equalizing the reaction equation:
- 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.
- 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product
- 3. Select the coefficient of the substance with the most complex chemical formula equal to 1
For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:
Balancing C atoms, H and last atoms O atoms
Methana combustion reaction
CH₄ (g) + O₂ (g) -> CO₂ (g) + H₂0 (g)
We give the most complex compounds, namely Methane, we give the number 1
So the reaction becomes
CH₄ (g) + aO₂ (g) -> bCO₂ (g) + cH₂0 (g)
C atom on the left 1, right b, so b = 1
H atom on the left 4, right 2c, so 2c = 4 ---> c = 2
Atom O on the left 2a, right 2b + c, so 2a = 2b + c
2a = 2.1 + 2
2a = 4
a = 2
The equation becomes:
CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)
<h3><em>Learn more</em></h3>
the combustion of octane in gasoline
hydrogen and excess oxygen
Keywords: methane, combustion, hydrocarbons, equalization of reaction equations
