Sorry this is a tricky one IDK I'll ask some others to help you

Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
w=21/6
w=3.5
Step-by-step explanation:
I hope it's helps you
Answer:
C IS 36 CUZ 12X3=36
Step-by-step explanation:
sry i only can solve c