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kow [346]
3 years ago
14

The Bobcats had a win-loss record of 41-23 before their star player, Melissa, got injured. Melissa didn’t play in any more games

, and the Bobcats finished the season with an overall win-loss record of 54-34. What is the absolute difference in the Bobcats’ win percentages with and without Melissa? Express your answer to the nearest whole number.
Mathematics
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

The win percentage decreased by 10%

Step-by-step explanation:

First you need to fin the total games played right before Melissa got Injured

41+23=64

Then you need to find the win percentage by making a fraction of wins over total games

wins/total games = 41/64 = 64%

Then you need to find the number of games played after Melissa got injured

54-41 = 13 wins

34-23 = 11 losses

13+11 = 24 total games played without Melissa

You find that win percentage similarly to the first time

wins/total games = 13/24 = 54%

Then you find the difference in the percentages and there you have it!!

64% - 54% = 10%

It decreased as well therefore the answer is...

It decreased by 10%

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Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

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B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

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Your problem could have errors that's why it can't be solved. You do not have to worry because it happens sometimes. 

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Step-by-step explanation:

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