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algol [13]
3 years ago
13

Write as a decimal 0.068%

Mathematics
2 answers:
Goryan [66]3 years ago
8 0
0.068\% =0.00068
marysya [2.9K]3 years ago
6 0
Solutions in the picture

Good luck :)

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the expression 5n+2 can be used to find total cost in dollars of bowling where n is the number of games bowled 2 represents the
exis [7]
So justsubsitue 3 for n
5(3)+2
15+2
17
answer is 17
3 0
3 years ago
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An actor invested some money at 5% simple interest, and $41,000 more than 4 times the amount at 9%. The total annual interest ea
NARA [144]

Answer:

  • The amount invested at 5%=$77,000
  • The amount invested at 9%=$349,000

Step-by-step explanation:

  • Let the amount invested at 5% simple interest =$x

He invested $41,000 more than 4 times the amount at 9%.

  • This amount is: $(4x+41000)

Total Annual Interest Earned = $35,260

Therefore, Time=1 year

Simple Interest=\frac{Principal X Rate X Time}{100}

Therefore, his total interest

=Interest from Investment 1 + Interest from Investment 2

35260=\left(\frac{x*5*1}{100} \right)+\left(\frac{4x+41000*9*1}{100} \right)\\35260=0.05x+(0.36x+3690)\\35260-3690=0.05x+0.36x\\31570=0.41x\\\text{Divide both sides by 0.41}\\x=\$77000

Therefore:

The amount invested at 5%=$77,000

The amount invested at 9%=$(4*77,000+41000)=$349,000

6 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
2 years ago
HELP! How do translations relate to shapes plz explain
Vlada [557]

Answer:

well on the x and y coordinate graph the the translation is what moves the shape

6 0
2 years ago
If f(x)=3x+2 what is the equation for f^-1(x)
Elden [556K]

Answer:

  f^-1(x) = (x -2)/3

Step-by-step explanation:

To find the inverse function, swap x and y, then solve for y.

  y = 3x +2 . . . . given function

  x = 3y +2 . . . . inverse relation

  x -2 = 3y . . . . subtract 2

  (x -2)/3 = y . . . divide by 3

f^-1(x) = (x -2)/3 . . . . in functional form

4 0
3 years ago
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