Two teams of nine members each engage in tug-of-war. Each of the first team's members has an average mass of 68 kg and exerts an
1 answer:
You might be interested in
Answer:
1.196 μm
Explanation:
D = Screen distance = 3 m
= Wavelength = 598 m
y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm
d = Slit distance
For first dark fringe
Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm
The maximum value of θ of such the ropes (with a maximum tension of 5,479 N) will be able to support the beam without snapping is:
We can apply the first Newton's law in x and y-direction.
If we do a free body diagram of the system we will have:
x-direction
All the forces acting in this direction are:
(1)
Where:
- T(1) is the tension due to the rope 1
- T(2) is the tension due to the rope 2
Here we just conclude that T(1) = T(2)
y-direction
The forces in this direction are:
(2)
Here W is the weight of the steel beam.
We equal it to zero because we need to find the maximum angle at which the ropes will be able to support the beam without snapping.
Knowing that T(1) = T(2) and W = mg, we have:
T(1) must be equal to 5479 N, so we have:
Therefore, the maximum angle allowed is θ = 37.01°.
You can learn more about tension here:
I hope it helps you!