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3 years ago

A golf club hits a 0.0459 kg golf ball

Physics

1 answer:

anastassius [24]3 years ago

8 0

Answer:

2.933 kg m/s

Explanation:

impulse = change in momentum

impulse = mass ( final velocity - initial velocity )

= 0.0459 ( 63.9 - 0 )

= 0.0459 × 63.9

= 2.93301 kg m/s

or = 2.933 kg m/s up to 4 significant figures

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3 years ago

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3 years ago

An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m

Tomtit [17]

Explanation:

We'll need two equations.

v² = v₀² + 2a(x - x₀)

where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

x = x₀ + ½ (v + v₀)t

where t is time.

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3 years ago