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2 years ago

A golf club hits a 0.0459 kg golf ball

Physics

1 answer:

anastassius [24]2 years ago

8 0

Answer:

2.933 kg m/s

Explanation:

impulse = change in momentum

impulse = mass ( final velocity - initial velocity )

= 0.0459 ( 63.9 - 0 )

= 0.0459 × 63.9

= 2.93301 kg m/s

or = 2.933 kg m/s up to 4 significant figures

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What is the average de Broglie wavelength of oxygen molecules in air at a temperature of 27°C? Use the results of the kinetic th

asambeis [7]

Answer:

$\lambda = 2.57 \times 10^{-11} m$

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2 years ago

A(n) 0.5 kg soccer ball approaches a player horizontally with a speed of 10.6 m/s. The player illegally strikes the ball with he

Llana [10]

Answer: - 25.2 kgm/s

Explanation: The mass of the ball is 0.5kg, and the initial velocity = 10.6m/s.

The final velocity is in opposite direction of the initial hence final velocity (v) = - 19.9 m/s

Impulse = change in momentum = final momentum - initial momentum.

Final momentum = mass × final velocity

Final momentum = - 19.9 × 0.5

Final momentum = - 9.95 kgm/s

Initial momentum = mass × initial velocity

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Change in momentum = - 25.2 kgm/s

The negative sign implies that the change in momentum is the opposite direction relative to the first.

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