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tia_tia [17]
3 years ago
6

A neon light consists of a glass tube with metal wires at each end. When connected to a high-voltage source, the gas glows.

Physics
2 answers:
ivolga24 [154]3 years ago
8 0
Can confirm C is correct
natima [27]3 years ago
8 0

Answer:

THE ANSWER IS C

Explanation:

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A rock dropped from a 20 meter bridge falls into the river below. How long did it take to reach the water? What velocity did it
Brut [27]

Answer:

2 s, -20 m/s

Explanation:

Given:

y₀ = 20 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t and v

y = y₀ + v₀ t + ½ at²

0 = 20 + 0 + ½ (-9.8) t²

0 = 20 − 4.9 t²

t ≈ 2 s

v² = v₀² + 2a(y − y₀)

v² = 0 + 2(-9.8)(0 − 20)

v ≈ ±20 m/s

Since the rock is falling, v = -20 m/s.

6 0
3 years ago
A woman with a mass of 60 kg runs at a speed of 10 m/s and jumps onto a giant 30 kg skateboard initially at rest. What is the co
lesya692 [45]

Answer:

The combined speed of the woman and the skateboard is 6.67 m/s.

Explanation:

It is given that,

Mass of woman, m₁ = 60 kg

Speed of woman, v = 10 m/s

The woman jumps onto a giant skateboard of mass, m₂ = 30 kg

Let V is the combined speed of the woman and the skateboard. It can be calculated using the conservation of momentum as :

60\ kg\times 10\ m/s+30(0)=(60\ kg+30\ kg)V

On solving the above equation we get V = 6.67 m/s

So, the combined speed of the woman and the skateboard is 6.67 m/s. Hence, this is the required solution.

7 0
3 years ago
How do the speeds of sound and light waves compare?
Oxana [17]

Answer:light waves travel faster than sound waves.

Explanation:

5 0
3 years ago
The crate, which has a mass of 100 kg, is subjected to the action of the two forces. If it is originally at rest, determine the
marin [14]

Explanation:

Below is an attachment containing the solution.

3 0
3 years ago
A total charge of 6.3×10?8 C is distributed uniformly throughout a 2.7-cm radius sphere. The volume charge density is:
AlladinOne [14]

Answer:

7.6\cdot 10^{-4} C/m^3

Explanation:

The volume charge density is given by:

\rho = \frac{q}{V}

where

q is the charge

V is the volume of the sphere

In this problem, we have:

q=6.3\cdot 10^{-8} C is the charge

r=2.7 cm=0.027 m is the radius of the sphere, so its volume is

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (0.027 m)^3=8.24\cdot 10^{-5} m^3

So, the volume charge density is

\rho = \frac{6.3\cdot 10^{-8} C}{8.24\cdot 10^{-5} m^3}=7.6\cdot 10^{-4} C/m^3

8 0
3 years ago
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