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In-s [12.5K]
3 years ago
15

Mr. Brown's class is collecting books for a book drive. They started with 2 books. On the first day, they had 6 books. On the se

cond day they had 18 books. Write an equation that models this situation.
A) y = 4x + 2
B) y = 2(3)x
C) y = 3x + 2
D) y = x2 + 2
Mathematics
2 answers:
Nata [24]3 years ago
8 0

Answer:

The equation which models the equation is given by :

\bf y = 2\cdot 3^x

Step-by-step explanation:

Mr. Brown's class is collecting books for a book drive.

They started with 2 books.

Now, x is the number of days

A). y = 4x + 2

on day 1, x = 1

⇒ y = 6

On day 2 , x = 2

⇒ y = 10 but on day 2 Number of books he had is given to be 18

So, This option is rejected

B). y = 2\cdot 3^x

on day 1, x = 1

⇒ y = 6

On day 2 , x = 2

⇒ y = 18

So, This option is correct

C). y = 3x + 2

on day 1, x = 1

⇒ y = 5 but on day 1 Number of books he had is given to be 6

So, This option is rejected

D). y = x² + 2

on day 1, x = 1

⇒ y = 3 but on day 1 Number of books he had is given to be 6

So, This option is rejected

Therefore, The equation which models the equation is given by :

\bf y = 2\cdot 3^x

elena-s [515]3 years ago
5 0

Answer:

the answer is b i click it and it was right

y=2(3)^x

Step-by-step explanation:

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In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho
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Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be \frac{42}{7} C^{\circ}.


Additionally, this can be solved by equations:

\dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = \dfrac{x \,\textrm{C}^{\circ}}{1 \,\textrm{hour}}

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3 years ago
Cos(x+y)/cos(x)sin(y)=cot(y)-tan(x)
zhuklara [117]
So there is an identity we'll need to use to solve this:

cos(x+y) = cosxcosy - sinxsiny

replace the numerator with the right hand side of that identity and we get:

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Separate the numerator into 2 fractions and we get:

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