If the boat is floating, then it's just sitting there, and not accelerating
up or down. That means the vertical forces on it must be balanced.
So if its weight (acting downward) is 100 newtons, then the buoyant
force on it (acting upward) must also be 100 newtons.
Answer:
the moment of inertia of the wheel is 0.408 kg.m²
Explanation:
Given;
tangential force applied to the wheel, f = 90 N
radius of the wheel, r = 0.15 m
initial angular speed of the wheel, ω₁ = 0
final angular speed of the wheel, ω₂ = 14.3 rev/s
time of motion of the wheel, t = 2.72 s
The tangential acceleration of the wheel is calculated as;
where;
is the angular acceleration
The mass of the wheel is calculated as;
F = ma
m = F/a
m = (90)/(4.96)
m = 18.15 kg
The moment of inertia of the wheel is calculated as;
I = mr²
I = 18.15 x (0.15)²
I = 0.408 kg.m²
Therefore, the moment of inertia of the wheel is 0.408 kg.m²
Answer:
P₁ = 2.215 10⁷ Pa, F₁ = 4.3 106 N,
Explanation:
This problem of fluid mechanics let's start with the continuity equation to find the speed of water output
Q = A v
v = Q / A
The area of a circle is
A = π r² = π d² / 4
Let's look at the speeds at each point
v₁ = Q / A₁ = Q 4 /π d₁²
v₁ = 10 4 /π 0.5²
v₁ = 50.93 m / s
v₂ = Q / A₂
v₂ = 10 4 /π 0.25²
v₂ = 203.72 m / s
Now we can use Bernoulli's equation in the colon
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
Since the tube is horizontal y₁ = y₂. The output pressure is P₂ = Patm = 1.013 10⁵ Pa, let's clear
P₁ = P2 + ½ rho (v₂² - v₁²)
P₁ = 1.013 10⁵ + ½ 1000 (203.72² - 50.93²)
P₁ = 1.013 10⁵ + 2.205 10⁷
P₁ = 2.215 10⁷ Pa
la definicion de presion es
P₁ = F₁/A₁
F₁ = P₁ A₁
F₁ = 2.215 10⁷ pi d₁²/4
F₁ = 2.215 10⁷ pi 0.5²/4
F₁ = 4.3 106 N
Answers:
a) 122.5 m
b) 50 m
Explanation:
Here we are dealing with projectile motion, where we can use the following two equations that model the parabolic motion of the stone after being thrown from the window:
(1)
(2)
Where:
is the height of the stone when it hits the ground
is the initial height of the stone
is the initial velocity of the stone
since we are told the stone was thrown horizontally
is the time the stone is in air
is the horizontal distance the stone travelled
Knowing this, we can answer the questions:
a)Initial height of the stone:
In this case we will isolate from (1):
(3)
(4)
(5) This is the initial height
b) Horizontal distance:
In this case we will use equation (2):
(6)
(7) This is the horizontal distance
A) 10÷8.5
b) 120÷10
c) answer A÷Answer B.
sure on first two, not so sure on C.