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vlabodo [156]
3 years ago
6

Coherent green light shines on a double slit with spacing 241um. This results in a diffraction pattern consisting of a central m

aximum and several lines to either side. When the green light is replaced with red light, the distance between the central maximum and the next line
O Becomes closer
O Becomes brighter
O Becomes dimmer
O None of the above
O Becomes greater
Physics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

Becomes greater

Explanation:

Distance between the central maxima and the next line increase with the wavelength i.e.

d =\frac{3 \lambda L}{2a}

As, the wavelength of the red light is greater than the wavelength of the green light, thus, the distance between  the central maxima and the next line becomes greater.

Option 5 is correct.

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A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp
Anna71 [15]

\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}

Explanation:

       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

       So, in the current problem, the natural length of the spring is not required to find the spring constant k.

       \text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}

∴ The spring constant of the spring = 2500\text{ }\frac{kg}{s^{2}}

4 0
3 years ago
Which of the following is not an essential feature of scientific explanations?
sineoko [7]

Answer:

D I think I might be wrong its been a while scense I did something like that

4 0
3 years ago
"
Volgvan

Answer:

The height is : 60.025 m

Explanation:

The flowerpot falls off the balcony with zero launch angle

Given the time of fright as 3.5 s then ;

The formula to apply is ;

T=\sqrt{\frac{2H}{g} }\\\\3.5=\sqrt{\frac{2H}{9.8} }

3.5²= 2H/9.8

12.25 =2H/9.8

12.25 * 9.8 = 2H

120.05 = 2H

120.05/2 = H

60.025 =H

7 0
3 years ago
You have two contentious friends, Chris and Pat, and you’ve quickly discovered that they need you to resolve arguments they have
pshichka [43]

Answer:

v_average = (d₂-d₁) / Δt

this average velocity is not necessarily the velocity of the extreme points,

Explanation:

To resolve the debate, it must be shown that the two have part of the reason, the space or distance between the two points divided by time is the average speed between the points.

             v_average = (d₂-d₁) / Δt

this average velocity is not necessarily the velocity of the extreme points, in the only case that it is so is when there is no acceleration.

Therefore neither of them is right.

3 0
3 years ago
Remember KE=M*V2/2…
 A model airplane moves twice as fast as another identical model airplane. Compared with the kinetic energy
pishuonlain [190]

Answer: 4 times as much

Explanation:

4 0
2 years ago
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