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UNO [17]
2 years ago
12

Help plssssss would be highly appreciate ❤️❤️

Physics
2 answers:
victus00 [196]2 years ago
7 0

Answer:

A

Explanation:

anastassius [24]2 years ago
4 0

Answer:

I beleive B because its on land and the tecnotic plates are moving opposite directions pulling the ground into a tear like hole

Explanation:

what happen when you take two sides of something and pull opposite directions right it tears the same will happen to the groung.

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A cord of mass 0.65 kg is stretched between two supports 8.0 m apart. If the tension in the cord is 120 N, how long will it take
DedPeter [7]

The time taken by the pulse to travel from one support to the other is 0.208 s.

<h3>Given:</h3>

The mass of the cord is m = 0.65 kg.

The distance between the supports is, d = 8.0 m.

The tension in the cord is T = 120 N.

The time taken by the pulse to travel from one support to the other is given as,

v=\frac{d}{t}

t=\frac{d}{v}

Here, v is the linear velocity of a pulse. Its value is,

v=\sqrt{\frac{T d }{m} }

v=\sqrt{\frac{120 * 8}{0.65} }

v= 38.43 m/s

Then,

t=\frac{8}{38.43}

t=0.208 s

Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.

Learn more about tension here:

brainly.com/question/24994188

#SPJ4

7 0
1 year ago
Select the correct answer.
Murrr4er [49]

Answer:

I will choose the answer A

3 0
3 years ago
Select the correct answer.
skelet666 [1.2K]

Answer:

B is the best answer for the question

6 0
3 years ago
Read 2 more answers
Một dây nhôm dài 10 m khi ở 25 độ C. Biết khi nhiệt độ tăng thêm 1 độ C thì chiều dài 1m dây nhôm sẽ tăng thêm 0,024mm.
kondor19780726 [428]

Answer:

??????? what language is this. um A then

5 0
3 years ago
A charged particle enters a uniform magnetic field B with a velocity v at right angles to the field. It moves in a circle with p
alukav5142 [94]

A) d. 10T

When a charged particle moves at right angle to a uniform magnetic field, it experiences a force whose magnitude os given by

F=qvB

where q is the charge of the particle, v is the velocity, B is the strength of the magnetic field.

This force acts as a centripetal force, keeping the particle in a circular motion - so we can write

qvB = \frac{mv^2}{r}

which can be rewritten as

v=\frac{qB}{mr}

The velocity can be rewritten as the ratio between the lenght of the circumference and the period of revolution (T):

\frac{2\pi r}{T}=\frac{qB}{mr}

So, we get:

T=\frac{2\pi m r^2}{qB}

We see that this the period of revolution is directly proportional to the mass of the particle: therefore, if the second particle is 10 times as massive, then its period will be 10 times longer.

B) a. f/10

The frequency of revolution of a particle in uniform circular motion is

f=\frac{1}{T}

where

f is the frequency

T is the period

We see that the frequency is inversely proportional to the period. Therefore, if the period of the more massive particle is 10 times that of the smaller particle:

T' = 10 T

Then its frequency of revolution will be:

f'=\frac{1}{T'}=\frac{1}{(10T)}=\frac{f}{10}

6 0
3 years ago
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