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Andreas93 [3]
3 years ago
8

Water flows through a horizontal nozzle in steady flow at the rate of 10m3/s. The inlet and outlet diameters are d1 = 0.5m and d2

= 0.25m. Water exits the nozzle to the atmosphere. Calculate the pressure at the entrance to the nozzle and the force required to hold the nozzle in place. Neglect the weight of the nozzle. rho = 1000kg/m3, g = 10m/s2.
Physics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

P₁ = 2.215 10⁷ Pa, F₁ = 4.3 106 N,

Explanation:

This problem of fluid mechanics let's start with the continuity equation to find the speed of water output

        Q = A v

        v = Q / A

The area of ​​a circle is

       A = π r² = π d² / 4

Let's look at the speeds at each point

       v₁ = Q / A₁ = Q 4 /π d₁²

       v₁ = 10 4 /π 0.5²

       v₁ = 50.93 m / s

       v₂ = Q / A₂

       v₂ = 10 4 /π 0.25²

       v₂ = 203.72 m / s

Now we can use Bernoulli's equation in the colon

       P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Since the tube is horizontal y₁ = y₂. The output pressure is P₂ = Patm = 1.013 10⁵ Pa, let's clear

       P₁ = P2 + ½ rho (v₂² - v₁²)

      P₁ = 1.013 10⁵ + ½ 1000 (203.72² - 50.93²)

      P₁ = 1.013 10⁵ + 2.205 10⁷

      P₁ = 2.215 10⁷ Pa

la definicion de presion es

      P₁ = F₁/A₁

     F₁ = P₁ A₁

     F₁ = 2.215 10⁷ pi d₁²/4

     F₁ = 2.215 10⁷ pi 0.5²/4

     F₁ = 4.3 106 N

     

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Answer:

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Explanation:

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6 0
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A worker pushes a 7 kg shipping box along a roller track. Assume friction is small enough to be ignored because of the rollers.
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Answer:

a) Fₓ = 23.5 N

b) Net force = Fₓ

Explanation:

An image of the question as described is attached to this solution.

From the image attached, the forces acting on the box include the weight of the box, the normal reaction of the surface on the box, the applied force on the box and the Frictional force opposing the motion of the box (which is negligible and equal to 0)

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Hope this Helps!!!

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“How bright would the sun appear to an observer on Earth if the sun were four times farther from Earth than it actually is? Expr
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When the source moves to a new position that's 4 times as far away, its apparent brightness becomes (1/4^2) its original value.

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4 0
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A balanced 3-wire, 120/240V, single-phase circuit is connected so that the ungrounded conductors are from different transformer
sasho [114]

Answer:

0\%

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A 3-wire, 120/ 240 V circuit from a three-phase delta transformer contains two ungrounded conductors and one grounded conductor. The  grounded conductor carries the unbalanced current when the circuit is not balanced.

A neutral conductor has the same equal potential between it and all ungrounded conductors of a 3-wire system.

The current on the neutral conductor is 0\% percent of the ungrounded conductor current.

6 0
3 years ago
You have four fixed-volume containers at STP. Container A has 0.5 mol of gas in 11.2 L. Container B has 2 mol of gas in 22.4 L.
GarryVolchara [31]
Container A has 0.5 mol of gas in 11.2 L.
P = nRT/V = 0.5(0.08206)(273.15) / 11.2 = 1 atm

Container B has 2 mol of gas in 22.4 L.
P = nRT/V = 2(0.08206)(273.15) / 22.4 = 2 atm

Container C has 1 mol ofgas in 22.4 L. P = nRT/V = 1(0.08206)(273.15) / 22.4 =1 atm

Container D has 2 mol of gas in 11.2 L.
<span>P = nRT/V = 2(0.08206)(273.15) / 11.2 = 4 atm
</span>
Therefore, the correct answer from the choices is the first option, container A and C has equal pressures.
7 0
3 years ago
Read 2 more answers
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