Complementary angles add up to 90 degrees.
So to find A you would need to add A and B together and equal it to 90 (3x+25+5x-7=90)
Combine like terms together (8x+18=90)
Subtract 18 from night sides (8x=72)
Divide by 8 on both sides (x=9)
Then to find A substitute x into its equation (3(9)+25)=(27+25)=52
A=52 I think
Answer:
you won't roll the same number 5 times
Answer:
The angles are <u>155°</u> and <u>25°</u>.
Step-by-step explanation:
Given:
Two supplementary angles are in the ratio of 31:5.
Now, to find the angles.
The sum of two supplementary angles = 180°
Let the ratio of the angles be
.
So, according to question:
![31x+5x=180\°](https://tex.z-dn.net/?f=31x%2B5x%3D180%5C%C2%B0)
![36x=180\°](https://tex.z-dn.net/?f=36x%3D180%5C%C2%B0)
<em>Dividing both sides by 36 we get:</em>
![x=5](https://tex.z-dn.net/?f=x%3D5)
So, ![31x=31\times 5=155\°.](https://tex.z-dn.net/?f=31x%3D31%5Ctimes%205%3D155%5C%C2%B0.)
And, ![5x=5\times 5=25\°.](https://tex.z-dn.net/?f=5x%3D5%5Ctimes%205%3D25%5C%C2%B0.)
Therefore, the angles are 155° and 25°.
Hello! To solve for x means to isolate x:
y = x^2 + 7
y - 7 = x^2
sqrt(y - 7) = x
Answer:
x = sqrt(y - 7)
Hope this helps!