Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
This equation is written in <em>standard form</em>, so we need to change it into <em>slope-intercept form.</em>
<em />
3x = -y - 5
3x + y = -y + y - 5
3x + y = -5
3x - 3x + y = -5 - 3x
y = -5 - 3x
y = -3x - 5
The slope is classified as "m" in this type of equation, so, the slope is -3.
Best of Luck!
I think they are perpendicular to each other
Answer:
x+2
Step-by-step explanation:
if a to the power of b is equal to x then a to the power of b +2 is x+2
