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Airida [17]
3 years ago
12

Find the probability of at least 2 girls in 8 births. assume that male and female births are equally likely and that the births

are independent events.
Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0
At least two girls means either 2, 3 ... or 8 girls. 
Using the binomial law, we can write the probability in the form:
B(2,0.5)+B(3,05)+...+B(8,0.5)=0.0039(C_8^2+...+C_8^8)
Continue simplifying:
C_8^2+...+C_8^8=2^8-C_8^1=2^8-8=248\\\text{We deduce the probability of the event "at least two girls in birth ":}\\0.0039\times248=0.96\\\text{The above probability (0.96) means that the event is very likely}
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Hey ! 

I am going to explain what I did to get the answer...

I multiplied $29,160 by 30 = $874,800
Then I multiplied $84,460 by 30 = $2,533,800 

Then I subtracted the results = a difference of $1,659,000

So the answer to your question is, $1,659,000 is the difference. 

I hope I was able to help you out :D <span />
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3 years ago
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Point A is located at (3,4) and is rotated 90 degrees counterclockwise about the origin. What is the new point of A?
sineoko [7]

A'(- 4, 3 )

Under a counterclockwise rotation about the origin of 90°

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3 years ago
What is the standard numeral for nineteen million,seven hundred thousand
ivolga24 [154]
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7 0
3 years ago
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-ax
KIM [24]

Answer:

3

Step-by-step explanation:

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As we know the point (x=0; y=3) lies at the function's  graph.

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6 0
3 years ago
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Help!! Please im having trouble
bekas [8.4K]

Answer:

1.  5/6 ≥ 2/3

2. 1/5 ≤ 2/8

3. 9/10 ≥ 6/8

4. I can't see it's out of the pic

5. 7/8 ≥ 5/10

6. 2/5 ≥ 2/6

7. 1/3 ≤ 3/8

8. I can't see it's out of the pic.

9. 8/10 ≥ 3/4

10. 3/8 ≤ 11/12

11. 2/3 ≤ 10/12

12. Can't see :(

13. 3/8 ≤ 7/8

14. 2/4 = 4/8

15. 6/8 ≥ 8/12

16. Can't see

Step-by-step explanation: All you have to do is divide the numerator by the denominator to make it into a decimal. For instance....

5/6 = approximately 0.83

I hope this helps you! It took forever....



3 0
3 years ago
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