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pav-90 [236]
3 years ago
9

Two noncongruent triangles, each with side 6 cm and an angle measuring 40 degrees

Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0

Answer:

Two noncongruent triangles, each with side 6 cm and an angle measuring 40 degrees This might be it

Step-by-step explanation:

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Please help! tell whether x and y are proportional. if so, identify the constant of proportionality
sesenic [268]

Answer:

y = (1/2)x is proportional; (1/2)

Step-by-step explanation:

1. y= 1/2x   Proportional; constant of proportionality is 1/2.

2. y=2x + 7   Not proportional because of the non-zero y-intercept.

3. x= y + 2    Not proportional (same a reason as for #2)

8 0
3 years ago
A book 2 3/7 inches think and another book 3.56 inches thick , if he stacks the books about how tall will they be
bazaltina [42]

Answer:

About 6 inches tall.

Step-by-step explanation:

One book has a thickness of 2\frac{3}{7} inches.

Another book has a thickness of 3.56 inches

Converting 2\frac{3}{7} inches to decimals will give; 2.4285714286 inches

If the books are stacked together, they become 2.4285714286 inches + 3.56 inches = 5.988571429 inches tall or about 6 inches tall (answer rounded up to nearest whole number).

7 0
3 years ago
The length of a rectangle is 7 feet less than the twice the width the perimeter is 76
DedPeter [7]

Answer:

yes I sont now how tu understand

6 0
3 years ago
3x-(2x-1)=7x-(3*5x)+(-x+24)
Paraphin [41]

Answer:

\boxed{\boxed{\sf x=\frac{23}{10}}\: \sf or \:\boxed{x=2.3}}

_________________

\boxed{\sf Step\: By\:Step:- }

\sf 3x-\left(2x-1\right)=7x-\left(3\times \:5x\right)+\left(-x+24\right)

<u>Remove the parentheses:</u>

\to\sf 3x-\left(2x-1\right)=7x-3\times \:5x-x+24

<u>Combine like terms:</u>

\sf ^*7x-x=6x

\to\sf 3x-\left(2x-1\right)=6x-3\times \:5x+24

<u>Multiply 3 and 5x = 15x:-</u>

\to\sf 3x-\left(2x-1\right)=6x-15x+24

<u>Combine like terms:</u>

\sf ^*6x-15x=-9x

\to\sf 3x-\left(2x-1\right)=-9x+24

<u>Expand: 3x-(2x-1)= x+1</u>

\to\sf x+1=-9x+24

<u>Subtract 1 from both sides:</u>

\to\sf x+1-1=-9x+24-1

\to\sf x=-9x+23

<u>Add 9x to both sides:</u>

\to\sf x+9x=-9x+23+9x

\to\sf 10x=23

<u>Divide both sides by 10:</u>

\to\sf \cfrac{10x}{10}=\cfrac{23}{10}

\to\sf x=\cfrac{23}{10}

<u>________________________________</u>

3 0
3 years ago
pls help!? with all 4 Questions I would rlly appreciate your help thx to plp who help me I will improve on my math and be way be
aliina [53]
7.6=w/12
w=7.6(12)
w=91.2

x/2=20
x=20(2)
x=40

8.3x=41
x=41(8.3)
x=340.3

54=r/3
r=54(3)
r=162








6 0
3 years ago
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