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murzikaleks [220]
3 years ago
8

Find the measure of each exterior angle of the regular polygon.

Mathematics
2 answers:
Ivanshal [37]3 years ago
4 0

Answer:

  • 45°

Step-by-step explanation:

Sum of exterior angles is 360° and there are 8 angles

<u>Each exterior angle measures:</u>

  • 360°/8 = 45°
n200080 [17]3 years ago
3 0

Answer:

720/8=90°

i guess.......

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Scott bought a pen and received change of $4.75 in 25 coins, all dimes and quarters. How many of each kind did he receive?
dangina [55]

Answer:

He received 10 dimes and 15 quarters.

Step-by-step explanation:

Dimes = $0.10

Quarters = $0.25

Variable x = dimes

Variable y = quarters

Create a pair of linear equations:

0.10x + 0.25y = 4.75

x + y = 25

Isolate any variable, using an equation of your choice:

x + y = 25

x = 25 - y

Plug in this new value of x into the other equation:

0.10(25 - y) + 0.25y = 4.75

Use the distributive property:

2.5 - 0.10y + 0.25y = 4.75

Combine like terms:

2.5 + 0.15y = 4.75

Isolate variable y:

0.15y = 2.25

y = 15

Plug in the value of y into any equation:

x + y = 25

x + 15 = 25

Isolate variable x:

x = 10

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A number, f is positive
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X+0.5y=1.5 solve for y
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Step-by-step explanation:

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3 years ago
B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing
kenny6666 [7]

Answer:

\boxed{ \boxed{ \sf {Marked \: price \:  = Rs \: 1500}}}

\boxed{ \bold{ \boxed{ \sf{Selling \: price =  \: Rs \: 1230}}}}

Step-by-step explanation:

Let Cost price ( C.P ) be x

<u>Finding </u><u>the </u><u>Marked </u><u>price </u><u>and </u><u>selling </u><u>price </u>

Marked price = \sf{x + 20\% \: of \: x}

⇒\sf{x +  \frac{20}{100}  \times x}

⇒\sf{ \frac{x \times 100 + 20x}{100} }

⇒\sf{ \frac{120x}{100} } ⇒ ( i )

Selling price = \sf{marked \: price \:  - 18\% \: of \: marked \: price}

⇒\sf{ \frac{120x}{100} -  \frac{18}{100}  \times  \frac{120x}{100} }

⇒\sf{ \frac{120x}{100}  -  \frac{54x}{250} }

⇒\sf{ \frac{120x \times 5 - 54x \times 2}{500} }

⇒\sf{ \frac{600x - 108x}{500} }

⇒\sf{ \frac{492x}{500} } ⇒ ( ii )

<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x </u><u>(</u><u> </u><u>Cost </u><u>price </u><u>)</u>

\sf{loss = cost \: price - selling \: price}

⇒\sf{20 = x -  \frac{492x}{500} }

⇒\sf{20  =  \frac{x \times 500 - 492x}{500} }

⇒\sf{20 =  \frac{8x}{500} }

⇒\sf{8x = 10000}

⇒\sf{x =  \frac{10000}{8} }

⇒\sf{x = \: Rs \:  1250}

Value of x ( cost price ) = Rs 1250

<u>Now</u><u>,</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>i </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>marked </u><u>price</u>

\sf{marked \: price =  \frac{120x}{100} }

⇒\sf{ \frac{120 \times 1250}{100} }

⇒\sf{   \: Rs \: 1500}

<u>Replacing </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>ii </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>selling </u><u>price</u>

\sf{selling \: price =  \frac{492 \: x}{500} }

⇒\sf{ \frac{615000}{500} }

⇒\sf{ \: Rs \: 1230}

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0
4 years ago
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